Question

A fluid manometer is open to the atmosphere as shown in figurel. If the gage pressure of the pressurized air is 0.07MPa, find the differential height h3 if hl=60cm and h2= 45cm. Mercury SG: 13.6 Ar! Methane S6= 0.47 Gasoline 56. 0.70 Figure I

Answer 1

mercury S=13.6 Pi = 0.07 MPa h, a 60cm. ba = 45 cm. methane SGT -0.47 Gasoline Sin = 0.70 Goncepts the which Fod Doing These Kind problems, of used elre listed below fluid in the level the pressure Same 1, Same in the will be Same. when down pressure increases 2. in a fluid moving we 3. when we moving up in a fluid pressure decreases. marked some in the points, i have figure at 8 (see point !) Pressure Pressure ent А Pressure A = Pressure at at 0 + P methane ghi Boara See concept point & Pressure at Pressure at B- Ping ghz (see concept point 3) P = 0.67 MPa gauge.

Applying those three and concepts Write pressure 0 limb and through the prom point till point 6 Po + Pomerans ghe - Phny g bu + gas I bg = Pam ao 0.07x10 + (0.4761006 9.81X0.6) - (13.681000x9.8140.45) +(0.7x100x 9.81x hy) = 0 + =0 @4 60037 + 6867 bz 7x10 + 2766.42 baa-4.854 m is the point a shows that the bere -ve in sign D point level of point the 11854 m above limb.