From the graph
At x = 0 f(x) =4
i.e f(0)=4
On checking the given options
A) f(0)= -e^0+3 = -1+3 =2
B)f(0)= e^0+4 = 1+4=5
C)f(0)=e^0+4= 1+4=5
D)f(0)=e^0+3 = 1+3 = 4
So, the answer is option D
i.e f(x)=e^-x + 3
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please show work
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