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Its not 2.25x10-5


7. [Ipt] The flowmeter in the figure on the right shows a difference in height, h = 5.80 cm, on an oil pipeline 202 cm2 in cross section. If the narrow section of the pipeline (on the right) has a diameter of 9.0 cm, what is the pipeline flow rate?
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From Bernoullis equation, 2 2 2(R-P 2(P -P 22-1 From the equation of continuity Hence, the velocity of the fluid through area A is as follows:From the given data, the change in pressure is as follows: Hence, the velocity of the fluid is as follows 2gH Calculate the flow rate of the fluid as follows: The expression for the flow rate is as follows: 2gH From the given data, the area of cross-sections are as follows: 202 cm and - 202x104 m2 9.0x102 m 2Therefore, the flow rate of the fluid is as follows: 2 9.8 m/s2 ) (5.80x102 m y (202x10-4 m2 )2-(63.61 7x10-4 m 2 )2 =(202×10-4 m2)(63.617×10-4 m2) 0.007147 m3/s

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