A 33-? resistor and a 25-? resistor are connected in parallel, and the combination is connected across a 280-V dc line.
(a) What is the resistance of the parallel
combination?
---------- ?
(b) What is the total current through the parallel
combination?
------------- A
(c) What is the current through each resistor?
I33? = -------------- A
I25? = -------------- A
a) Rnet = 33*25/(33+25)
= 14.22 ohms
b) I = V/Rnet
= 280/14.22
= 19.7 A
c) I33 = I*25/(33+25)
= 19.7*25/(33+25)
= 8.49 A
d) I25 = I*33/(25+33)
= 19.7*33/(33+25)
= 11.2 A
a)
1/R=1/33 + 1/25
R=14.22 ohms
b)
V=RI so I=V/R= 280/14.22=19.68 A
c)
I33=V/R: I=280/33=8.48 A
I25=V/R: I=280/25 = 11.2 A
Req = 33*25/33+25 = 14.22 ohm (ans)
Net current ,Ir=V/Req =280/14.22 =19.69 A (ans)
I33 =Ir*25/58 =8.49 A (ans)
I25 = Ir*33/58 = 11.20 A (ans)
1. Reff. = R1 * R2 / ( R1+R2)
= 25*33 / 58 = 14.22 OHM
2. v = I * Reff.
I = V/R = 280/14.22 = 19.69A
3. I1 = V/R1 = 280/33 = 8.48A
I2 = V/R2 = 280/25 = 11.2A
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