Question

А о 50 mm B 125 mm T

1.
The gears have full depth teeth and are manufactured from AISI 1020 CD (Through hardened grade 1 steel) to 248 BHN and have a module of 3 mm/tooth with a pressure angle of 20 degrees. The motor develops a peak power of 44.54 kW at 1,869 rpm. Use a factor of safety of 8 from the yield strength for the shaft. The shaft is made from AISI 1040 CD steel. Estimate the maximum bending moment in shaft CD. Give your answer in Nm. Take the shaft lengths as: AE = 200 mm, BE = 150 mm, CF = 132 mm and DF = 194 mm. (Note: work to 3 decimal places).

2.
The gears have full depth teeth and are manufactured from AISI 1020 CD (Through hardened grade 1 steel) to 248 BHN and have a module of 3 mm/tooth with a pressure angle of 20 degrees. The motor develops a peak power of 92.58 kW at 951 rpm. Use a factor of safety of 4 from the yield strength for the shaft. The shaft is made from AISI 1040 CD steel. Estimate what the torque is in shaft CD. Give your answer in Nm. Take the shaft lengths as: AE = 200 mm, BE = 150 mm, CF = 0.19 mm and DF = 175 mm. (Note: round off to 3 decimal places)

3.
The gears have full depth teeth and are manufactured from AISI 1020 CD (Through hardened grade 1 steel) to 248 BHN and have a module of 3 mm/tooth with a pressure angle of 20 degrees. Take the maximum bending moment as 1,116.03 Nm and the maximum torque as 1,763.17 Nm. Use a factor of safety of 3.5 from the yield strength for the shaft. The shaft is made from AISI 1040 CD steel. Estimate what the diameter of shaft CD is. Give your answer in mm. Take the shaft lengths as: AE = 200 mm, BE = 150 mm, CF = 150 mm and DF = 175 mm. (Note: round off to 3 decimals).

Answer 1

Solution - Given 3 44.54 X10 N: 1869 rpm r - 50 mm P = 2nNT 60 3 44.54710- 2x TX1869XT 60 T: 44.54x103x60 2x X1869 고 = 357. HINm and Tangential force on Pinjon Fexrp T Ftxo 050 = 375.41 Nm Ft : 4550N

for gear on of shaft CD, it will put downward force A R 45 50 Nm for shaft CD , EBD F TRA TRE 132 --194 Considering point A Rat Rp = F t = 4550W moments about Fc X9.132 = Rp X0:326 Rp 21842 331 N RA = 2767. 669 N és Maximum Mament on shaft CD : RAXO.132 2707X 0.132 = 357.410Nm 357 Nm Ans P = 92.58 KW N: 951 rpm LAE = 200mm : 0.2m BE = 150mm 0.15m ICR : 190mm -0.19 m IDF : 175 mm = 0.175 m 3 = & TNT 60 92.58X10 = 2x1TX 951XT 60 1 - 929-625 Nm force on the the pinion Fexrp = I F4x0.050 - J£9.625

F = 18,5985 N for torque o on shaft CD T = Ft XrG 1859 2 X 0.125 2384.063 Nm 3. Given Max. Torque T 1763 17 Nm Yield Max Bending Mament, M = 1116.03 Nm Strength of 1080 CD steel voiy factor of safety co Working Sték ay 350 MPa and Factor : 3.5 F.o.s = 100 MPa = 350 3.5 and o 3 38Me Nd3 where Me : Equivalent Bending Moment Me (M+NM²+2 2 = 1 (1116-03 + 2/(1116-23) + (1763-133 2 Me: 1601-361 Nm 6 TOOX 100 32x1601.361 Tid 3 d3 : 321601.36) X 100 X 10 6 54.638 mm d :