Question

If 28.6 mL of silver nitrate solution reacts with excess potassium chloride solution to yield 0.839 g of precipitate, what is the molarity of silver ion in the original solution?​

Answer 1

AgNO3 + KCl --> AgCl (s) + KNO3

Molar mass of AgCl = 143.32 g/mol

Moles of AgCl = 0.839 g/143.32 g/mol => 0.00585 moles

Moles of AgCl = moles of AgNO3 => 0.00585 mol

28.6 mL = 0.0286 L

Molarity = moles of solute / Ltr of solution

Molarity of AgNO3 = 0.00585 mol / 0.0286 L

= 0.2047 M

Answer = 0.2047 M