Question

Matlab Code if available

Problem 04 mm us(0 In the circuit, the voltage source Vs(t) frequency, amplitude and phase are 22 kHz, 10 V and 0.25 rad correspondingly; Rs=4 Ohm, Ri=12 Ohm, R2=9 Ohm, R3=2 Ohm, L1=0.11 mH, L2=0.13 mH, C= 1.4 uF ("u"="micro"). Part A. Using any appropriate techniques, find the parameters of Thevenin equivalent circuit with respect to the ports "a" and "b". Present the Thevenin source in the polar form and the Thevenin impedance in the algebraic form. 1) Thevenin source amplitude:(Unit: V) Submit Answer Incorrect. Tries 3/5 Previous Tries 2) Thevenin source phase in rads (Units: rad) Submit Answer Incorrect. Tries 1/5 Previous Tries 3) Real part of Thevenin equivalent impedance(Ohm) Submit Answer Tries 0/5 4) Imaginary part of Thevenin equivalent impedance(Ohm) Submit Answer Tries 0/5 Part B. Find the parameters of the matching load connected to the ports "a" - "b". 5) Find the real part of the matching load impedance. (Unit: Ohm) Submit Answer Tries 0/5 6) Find the imaginary part of the matching load impedance. (Unit: Ohm) Submit Answer Tries 0/5 7) Identify the type of equivalent circuit of the matching load (select the correct circuit type from the options below): Series connection of resistor and inductor. Series connection of resistor and capacitor. Submit Answer Tries 0/1 8) If you identified the equivalent circuit of the matching load as resistor and inductor in series, enter the value of the series inductance in H. If you identified the equivalent circuit of the matching load as resistor and capacitor in series, enter the value of the series capacitance in F. Note: even if you have answered the question (7) above incorrectly, you should still enter the correct values when answering this question. Submit Answer Tries 0/5

Answer 1

Vset solni- Cuven the electric circuit as 2 osoa 2 2 2 woon oa 05 = 138.23 Kre = 14,3240 V (H) ob Cuven into; - Volt) . . Vm= lov f - 22khz - W = 25*22k % = 0.25 rad = x R = 42 Ri= 122 R2 - 9 R3 = 20 3 x 138.23 & 40118% L = o.limy – XL = 2 WL = 515.205 r L = 0.3 mn – Jwl, = 9x130 123 x 25 x 0113 x = 17.97 r (= 1.461f Xe 138.23x1 & 114*100 u35.17 r. - Thevning source amplitude :- Wh) - (vab) V R2 X2 wc W drz velty B to nodal analysis on B. Apply

Rth = & Ron= Therudux voltage & vab = 2,486 1-88.93 so its amplitude – 2.4.86 volt. & praxe – – 880130 = 93.07° phase – 1.589 sad. I 6 Thernung Impedance - Thev. Inp. by their first all the interneta for evaluation of sources replaced as 7 . impedance Rth - Rab R2 tua 2 3 & R32 z Dx83 22 & 2, 5XL) hobl 2. RefX L2 . L 7 = R + = Rz txe Rth = (Rs) 12,). + Z2) 11 Zz (RtX) - - 3 15.205) 80 R 113= 4x critxu 4212 +2150205) Gt R + XL (Rs 11 2) = 3.474 +0.4991 (Rp 11 +Z2 = (3.474 +0.4991 ) + ( 9+117.97) - 19.474 at 180469 ů

V kth= (12.474) + 18.469 i) + (2-35.17) - (Rth=Rab] (12.474+18.46git 235.17) Rth = 120.4327 - 27,550) (14.474 +813.299) 8th = 3.66 - 5. 177 i Ian Rth = 3.56 - 5.177 if on. Real past = 3.56 r.) * que 4) Imprinary post = 75. 177. on Ring -35.7777 (past – 3 : 5) - - since for the matelung load the impedance is of - Complex 2 = 2th Conjugate Z = (3.56 – 5.177i)* [2 = (3.56 +5.1778) is 6 7 (2 read - 3.56 d. (21)ing = 75.177 d. The tybe est load impedance the senex Connection of rexis for & Inductor.

au registon 2 80 the penies & indectors connection - - R-3.560 X = 75,1772 fwl= 75, 177 r. - 5. 177 m . 2 38, 23 L - 000374 my Aws
sry I have not available of matlab .