Question

write the molecular equation, ionic equation and net ionix equation

1. Lead (II) nitrate is reacted with potassium bromide to produce lead (II) bromide and potassium nitrate. Using the solubility chart, write the molecular equation, ionic equation, and net ionic equation. (S = soluble, I = insoluble) NO3 Pb2+ K a) Molecular equation [.75] b) lonic equation [.75] c) Net ionic equation [.75]

Answer 1

First for this we will write balanced molecular equation

Pb(NO₃)₂ (aq) + 2 KBr(aq) -----> PbBr₂ (s) + 2KNO₃(aq)

From the table we got to know that PbBr₂ is not soluble in nature

Now we will seperate aqueous species into its ions to write ionic equation

Which will be as follows

Ionic equation

Pb²⁺ +2NO₃^- + 2K⁺ + 2Br^- -----> PbBr₂ + 2K⁺ + 2NO₃^-

as we can see some species are present on both sides of the reaction

This are called spectator ions

If we remove this we get net ionic equation

Which will be as follows

Pb²⁺ + 2Br^- -----> PbBr₂

I hope this helps if you have any query or want more detailed explanation feel free to ask in the comments section below.