While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used electrodes to monitor the cell potential. Using the table of theoretical values and what you know of the metals to fill in the blanks below.
When writing equations: Use spaces only before and after a plus sign. For example, the reaction: Fe2++2e−→FeFe2++2e-→Fe would be entered as: Fe^2+ + 2e^- →→ Fe
| Galvanic Cell Consisting of: | Al3++3e−Al3++3e- | →→ | AlAl | -1.66 |
| Mg2++2e−Mg2++2e- | →→ | MgMg | -2.37 |
| E0cell Measured | 0.63 |
| Write the equation occuring at the anode. | →→ |
| Write the equation occurring at the cathode. | →→ |
| Shorthand Notation for the Cell: | l lI l |
| Oxidizing Agent: |
Al Mg `Mg2+ Al3+ |
| Reducing Agent: |
Al3+ Al Mg `Mg2+ |
| E0cell from Table Values (Theoretical Numbers above). | |
| E0cell Percent Error |
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While performing Lab 11, Electrochemistry, students connected 1
M solutions of the following metals and used...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used electrodes to monitor the cell potential. Using the table of theoretical values and what you know of the metals to fill in the blanks below. When writing equations: Use spaces only before and after a plus sign. For example, the reaction: Fe2+ + 2e → Fe would be entered as: Fe^2+ + 2e → Fe Galvanic Cell Consisting of: Cu²+ + 2e - Cu...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used electrodes to monitor the cell potential. Using the table of theoretical values and what you know of the metals to fill in the blanks below. When writing equations: Use spaces only before and after a plus sign. For example, the reaction: Fe2+ + 2e - → Fe would be entered as: Fe^2+ + 2e. → Fe Galvanic Cell Consisting of: Zn²+ + 2e -...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used electrodes to monitor the cell potential. Using the table of theoretical values and what you know of the metals to fill in the blanks below. When writing equations: Use spaces only before and after a plus sign. For example, the reaction: Fe2+ + 2e → Fe would be entered as: Fe^2+ + 2e. Fe Galvanic Cell Consisting of: Zn²+ + 2e Zn -0.76 +...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used electrodes to monitor the cell potential. Using the table of theoretical values and what you know of the metals to fill in the blanks below. When writing equations: Use spaces only before and after a plus sign. For example, the reaction: Fe2+ + 2e + Fe would be entered as: Fe^2+ + 2e^. ► Fe Galvanic Cell Consisting of: Cu2+ + 2e - Cu...
please I need answers to all these questions! Name 3 HW Electrochemistry Submit before Nov 20,...
please I need answers to all these questions!
Name 3 HW Electrochemistry Submit before Nov 20, 2019 at 12 PM D2L Submission: Submit one file containing all calculations and the original paper Assessments Assign ments HW Electrochemistry 1) Which two of the following half-reactions will combine to give the galvanic cell with the highest cell potential? Reduction Half-Reaction E (V) Metal Al3+ 3e- Al(s) Aluminum -1.66 Mn + 2e Mn(s) - 1.18 Manganese Zn 2e Zinc Zn(s) -0.76 Cr3 Зе-...
Instead of using zinc, a student accidentally used a 1 M solution of silver (Ag). Based...
Instead of using zinc, a student accidentally used a 1 M solution of silver (Ag). Based on the information in the table below, what would be the theoretical cell voltage, Eocell, when it is used in a galvanic cell with copper? Electrode Eo Ag+ + e- à Ag +0.80 V Cu2+ + 2e- à Cu +0.34 V Pb2+ + 2e- à Pb -0.13 V Zn2+ + 2e- à Zn -0.76 V Al3+ + 3e- à Al -1.66 V
PART A: REDOX REACTIONS 1. For each of the metals, write the redox equations for reactions...
PART A: REDOX REACTIONS 1. For each of the metals, write the redox equations for reactions you observed in a table as shown below. Write NR for “no reaction” where none was observed. 2+ (**e.g., Cu + Zn → Cu + Zn , Ecell = 1.10 V) Cu(NO3)2 Pb(NO3)2 Zn(NO3)2 16 Cu(s) NR NR Pb(s) NR Zn(s) NR 2. Calculate the Eº for every cell, whether or not a reaction was observed, using equation (5) and values for the standard...
Candidate l: Zn(s) | Zn2+(aq,0.500 M) I Cu2+(aq, 1.00 M) Cu(s) Candidate 2: Pb(s) | Pb2+(aq,...
Candidate l: Zn(s) | Zn2+(aq,0.500 M) I Cu2+(aq, 1.00 M) Cu(s) Candidate 2: Pb(s) | Pb2+(aq, 0.500 M) || Cu2+(aq, 1.00 M) Cu(s) Candidate 3: Mg(s) | Mg2+(aq, 0.500 M) | Pb2+(aq, 1.00 M)| Pb(s) (a) 6 pts) Choose one of the candidate voltaic cells #1, #2, or #3. Draw a schematic cell diagram for the candidate voltaic cell of choice. Clearly label anode, cathode, electrodes, ions and their concentrations, salt bridge, and the flow of electrons. (b) (5 pts)...
A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the...
A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the following standard reduction half-cell potentials at 25∘C: VO2+(aq)+Ni2+(aq)2H+(aq)++2e−e−→ →Ni(s)VO2+(aq) +H2O(l)E∘=−0.23V E∘=0.99V) An electrochemical cell is based on these two half-reactions: Oxidation:Reduction:Ni(s)VO2+(aq,0.024M)+2H+(aq,1.4M)+e−→→Ni2+(aq,1.8M)+2e−VO2+(aq,1.8M)+H2O(l) Calculate the cell potential under these nonstandard concentrations. C) Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V ) Half-reaction E∘ (V ) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) − 0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) − 0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) − 0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) − 0.76...
Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is...
Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is related to the standard cell potential, Ecel, by the equation Reduction half-reaction (V) Ag+ (aq) + e-→Ag(s) Cu2+ (aq) + 2e-→Cu(s) 0.34 Sn (a) 4e-Sn(s 0.15 2H' (aq) + 2e-→H2 (g) Ni2+ (aq) + 2e-→Ni(s)-0.26 Fe2+ (aq) + 2e-→Fe(s)-0.45 Zn2+ (aq) + 2e-→Zn(s)-0.76 Al3+ (aq) +3e-→Al(s) -1.66 Mg2+ (aq) + 2e-→Mg(s) -2.37 0.80 n FEcell where n is the number of moles of electrons...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used electrodes to monitor the cell potential. Using the table of theoretical values and what you know of the metals to fill in the blanks below. When writing equations: Use spaces only before and after a plus sign. For example, the reaction: Fe2+ + 2e → Fe would be entered as: Fe^2+ + 2e → Fe Galvanic Cell Consisting of: Cu²+ + 2e - Cu...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used electrodes to monitor the cell potential. Using the table of theoretical values and what you know of the metals to fill in the blanks below. When writing equations: Use spaces only before and after a plus sign. For example, the reaction: Fe2+ + 2e - → Fe would be entered as: Fe^2+ + 2e. → Fe Galvanic Cell Consisting of: Zn²+ + 2e -...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used electrodes to monitor the cell potential. Using the table of theoretical values and what you know of the metals to fill in the blanks below. When writing equations: Use spaces only before and after a plus sign. For example, the reaction: Fe2+ + 2e → Fe would be entered as: Fe^2+ + 2e. Fe Galvanic Cell Consisting of: Zn²+ + 2e Zn -0.76 +...
While performing Lab 11, Electrochemistry, students connected 1 M solutions of the following metals and used electrodes to monitor the cell potential. Using the table of theoretical values and what you know of the metals to fill in the blanks below. When writing equations: Use spaces only before and after a plus sign. For example, the reaction: Fe2+ + 2e + Fe would be entered as: Fe^2+ + 2e^. ► Fe Galvanic Cell Consisting of: Cu2+ + 2e - Cu...
please I need answers to all these questions!
Name 3 HW Electrochemistry Submit before Nov 20, 2019 at 12 PM D2L Submission: Submit one file containing all calculations and the original paper Assessments Assign ments HW Electrochemistry 1) Which two of the following half-reactions will combine to give the galvanic cell with the highest cell potential? Reduction Half-Reaction E (V) Metal Al3+ 3e- Al(s) Aluminum -1.66 Mn + 2e Mn(s) - 1.18 Manganese Zn 2e Zinc Zn(s) -0.76 Cr3 Зе-...
PART A: REDOX REACTIONS 1. For each of the metals, write the redox equations for reactions you observed in a table as shown below. Write NR for “no reaction” where none was observed. 2+ (**e.g., Cu + Zn → Cu + Zn , Ecell = 1.10 V) Cu(NO3)2 Pb(NO3)2 Zn(NO3)2 16 Cu(s) NR NR Pb(s) NR Zn(s) NR 2. Calculate the Eº for every cell, whether or not a reaction was observed, using equation (5) and values for the standard...
Candidate l: Zn(s) | Zn2+(aq,0.500 M) I Cu2+(aq, 1.00 M) Cu(s) Candidate 2: Pb(s) | Pb2+(aq, 0.500 M) || Cu2+(aq, 1.00 M) Cu(s) Candidate 3: Mg(s) | Mg2+(aq, 0.500 M) | Pb2+(aq, 1.00 M)| Pb(s) (a) 6 pts) Choose one of the candidate voltaic cells #1, #2, or #3. Draw a schematic cell diagram for the candidate voltaic cell of choice. Clearly label anode, cathode, electrodes, ions and their concentrations, salt bridge, and the flow of electrons. (b) (5 pts)...
Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is related to the standard cell potential, Ecel, by the equation Reduction half-reaction (V) Ag+ (aq) + e-→Ag(s) Cu2+ (aq) + 2e-→Cu(s) 0.34 Sn (a) 4e-Sn(s 0.15 2H' (aq) + 2e-→H2 (g) Ni2+ (aq) + 2e-→Ni(s)-0.26 Fe2+ (aq) + 2e-→Fe(s)-0.45 Zn2+ (aq) + 2e-→Zn(s)-0.76 Al3+ (aq) +3e-→Al(s) -1.66 Mg2+ (aq) + 2e-→Mg(s) -2.37 0.80 n FEcell where n is the number of moles of electrons...
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