Question

Write a C++ code to make a simple program that imports the input file in and gets the results as specified

Please follow the instructions and paste the code below as the answer with a screenshot of the output to prove it worked.

Input file -> https://www.dropbox.com/s/444jofkchu6ylwr/names.txt?dl=0

Scoring Names You will be using the provided names.txt file, text file containing over five-thousand first names, and you will calculate a score for each name. Begin by reading the names from the file and sorting them in alphabetical order. Then, you will compute an alphabetical value for each name where A is 1, Bis 2, C is 3 and so on. The alphabetical value of a name is just the sum of the values of the letters in the name. To compute the name-score for a name, you simply multiply this alphabetical value by its position in the sorted list. For example, when the list is sorted into alphabetical order, COLIN, which is worth 3 15 12 9 14 53, is the 938th name in the list. So, the name-score for COLIN would be 938 53 49714. What is the sum total of all the name-scores in the file?

Answer 1

Notes:The name.txt given in the link could not be opened. So I create a test file that has 1000 names.So my program is based on 1000 names.U can change it to 5000 just by changing #define MAX 1000 to %define MAX 5000

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/* C++ program to read first names of 1000 peoples.store them in a
a file in alphabetical order . Then calculate name score of each name
and then calculate the total namescore of each employee*/
#include<iostream.h>
#include<fstream.h>
#include<stdlib.h>
#include<string.h>
#include<conio.h>
#include<ctype.h>
#define MAX 1000
//using namespace std;

//Structure defination
struct NameInfo
   {
   int sl;
   char name[25];
   unsigned long int namescore;
   };
//main program
int main()
   {
   ifstream fin;
   struct NameInfo namelist[MAX];
   char temp[25];
   //open the file containing the first names
   fin.open("names.txt",ios::in);

   if(fin.fail())
       {
       cout<<"unable to open the file!";
       exit(0);
       }
   int i=0,j,n;
   // read from file and store in the namelist
   while(!fin.eof())
       {
       namelist[i].sl=i+1;
       fin>>namelist[i].name;
       namelist[i].namescore=0;
       i++;
       }
   n=i;
   //Sort in alphabetical order
   for(j=1;j<n;j++)
       {
       strcpy(temp,namelist[j].name);
       i=j-1;
       while (i>=0 && strcmp(temp,namelist[i].name)<0)
           {
           strcpy(namelist[i+1].name,namelist[i].name);
           i--;
           }
       strcpy(namelist[i+1].name,temp);
       }
   //compute the namescore of each person
   char x;
   for(i=0;i<n;i++)
       {
       unsigned long int alphavalue=0;
       for(j=0;namelist[i].name[j]!='\0';j++)
           {
           x=toupper(namelist[i].name[j]);
           alphavalue+=(x-64);
           }
       namelist[i].namescore=namelist[i].sl*alphavalue;
       }

   //Compute the total name score of all persons
   unsigned long int totalnamescore=0;
   for(i=0;i<n;i++)
       {
       totalnamescore+= namelist[i].namescore;
       }

   //Print the names with namescore
   for(i=0;i<n;i++)
       {
       cout<<endl<<namelist[i].sl<<" "<<namelist[i].name<<" "<<namelist[i].namescore;
       }

   //print total name score
   cout<<endl<<"Total name score ="<<totalnamescore;
   return 0;
   }

//------------------------------------------------

output: o/p consist of 100 names so could send all . snap shot of the last page is below

E DOSBox 0.74, Cpu speed: max 100% cycles, Frameskip 0, Program: 77 WALTER 77183 78 WNANDA 42054 79 WARREN 77341 80 WAYNE 66640 81 WENDELL 73575 82 WENDY 69722 83 WESLEY 87487 84 WHITNEY 102336 85 WILBERT 87665 86 WILBUR 83810 87 WILFRED 75999 88 WILLARD 78052 89 WILLIAM 78131 90 WILLIE 69300 91 WILLIS 83244 92 WILMA 57536 93 WILSON 91356 94 WINIFRED 87472 95 35820 96 WOODROW 112548 97 YOLANDA 71784 98 YUETTE 96806 99 YUONNE 94905 TC 1000 ZACHARY 82000 otal name score -32607719