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3 For the network a. Find the total impedance Z and the total admittance Y. b. Find the current I.. c. Calculate I, using the
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Answer #1

E=60/20 [x2=122 from the circuit total impedarice ₂ will be Z= Jizel (9.1 j122) Tie, impedance of Parallel branch 1 [z=jan) i(d) Now Vc = Voltage Across Capacitor Ve= Jate -bosbeéx (-12) 23-0-5428, *cz- -5.2 +j3 volts L 122 Ve= 6 230 volts. I C 124-9

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