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3. Consider a person who chooses an amount of consumption c and non-working or leisure time R to maximize the utility functio

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Answer #1

Solution:-

Given that

U(R,c)=100R-R^2+c

c = consuption

R = leisure

Budget constraint :  C+wR=w\bar{L}+M ........(1)

\bar{L} = Max time available = 24

M = inital Income = 42

(3.1)

From (1),

C=w\bar{L}+M-wR

Put value of c in utility function and differentiate with respect to R

to get optimal value of R

U(R)=100R-R^2+w\bar{L}+M-wR

\frac{dU(R)}{dR}=100-2R-w

\frac{dU(R)}{dR}=0

100-2R-w=0

2R=100-w

R^*=\frac{100-w}{2}=50-\frac{w}{2} .......(2)

and  

C=w\bar{L}+M-wR

C=w\bar{L}+M-w(50-\frac{w}{2})

C=w\bar{L}+M-50w+\frac{w^2}{2}

C^*=(\bar{L}-50)w+\frac{w^2}{2}+M ......(3)

Put \bar{L} = 24 & M = 42 in eqn (3)

C^*=(24-50)w+\frac{w^2}{2}+42

C^*=42-26w+\frac{w^2}{2}

(3.2)

After tax,

Wage rate w' = (1 - t)w

Amount of tax collected = tw(\bar{L}-R)

New Budget constraint

C+w'R=w'\bar{L}+M

C+(1-t)wR=(1-t)w\bar{L}+M

C=(1-t)w\bar{L}+M-(1-t)wR

U(R,c)=100R-R^2+c

U(R)=100R-R^2+(1-t)w\bar{L}+M-(1-t)wR

\frac{dU(R)}{dR}=100-2R-(1-t)w

\frac{dU(R)}{dR}=0

100-2R-(1-t)w=0

2R=100-(1-t)w

R_1=\frac{100-(1-t)w}{2} New R

&  C=(1-t)w\bar{L}+M-(1-t)wR

C=(1-t)w\bar{L}+M-(1-t)w(\frac{100-(1-t)w}{2})

C=(1-t)w\bar{L}+M-50(1-t)w+\frac{(1-t)^2w^2}{2}

Put \bar{L} = 24, M = 42

C=24(1-t)w+42-50(1-t)w+\frac{(1-t)^2w^2}{2}

C_1=42+(24-50)(1-t)w+\frac{(1-t)^2w^2}{2}

C_1=42-26(1-t)w+\frac{(1-t)^2w^2}{2}

(3.3)

Amount of tax collected is given by T

T=tw(\bar{L}-R)

when  t=\frac{1}{3},\ w=\frac{3}{2},\ \bar{L}=24,\ R=50-\frac{w}{2}

T=\frac{1}{3}\times \frac{3}{2}[24-(50-\frac{3}{2}\times \frac{1}{2})]

T= \frac{1}{2}[24-(\frac{200-3}{4})]

T= \frac{1}{2}[24-\frac{197}{4}]

T= \frac{1}{2}[\frac{96-197}{4}]

T=\frac{-101}{8}

T=-12.625

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