Question

Problem Set 1: Chemical Equilibrium: Clave A) al chemical reactions have ceased B) the rates of the forward and reverse reactions are equal C) the rate constants of the forward and reverse reactions are equal D) the value of the equilbrium constant is 1 E) the limiting reagent has been consumed 6) The value of Kfor the equlbrium s794 at25 "C. What is the value o K for the equilbrium below? A) 397 B) 0035 2) Which one of the following will change the value ofan equalibrium constant? A) changing temperature B) adding other substances that do not react with any of the species nvelved in the equilibrium C) varying the intial concentrations of reactants D) varying the intial concentrations of products E) changing the volume of the reaction vessel C)28 D) 1588 E) 00013 7) The value of Kfor the equilbrium s 794 at 25 *C.At this temperature, what is the value of K for the 3.) Which of the following expressions is the correct equilibrium-constant expression for the equibrium between dinitrogen tetrexide and nitrogen dioxide? equilibrium below? A) 1588 8) 28 C)397 D)0.035 E) 00013 INO.J A) [NO,P IN,O,) NO,] )Consider he folowing chemical neaction A equilbrium in a particular esperiment the concentrations of HI, and HI were 0.15M 0.033M and 0.55M respectively The alue of K for this reaction is C) A) 23 C) 9.0x10" D)6.1 4.) The equlbrunconstant expression depends onthe the reaction Aj stoichiometry B) mechanism C) stoichiometry and mechanism D) the quantties of reactants and products initaly present E temperatuare of 61 9) A reaction vessel is charged with hydrogen odide which partaly decomposes to molecular hydrogen and iodne the system comes to equiterium at425 C P-0.708atm and PH ,-0.0960 atm The value of Ks 5) Given the following reaction at equilibrium at 4500 "C A) 6.80 x 10 A)00160 8)0.0821 C) 7.23 B) 130 x 10 C) Kp cannot be caloulated for this gas reaction when the volume of the reaction vessel is not given D)54.3 o) 2.70 x 10 E) 723 E) 184 x 10

Answer 1

1. at equilibrium, the rate constants of the forward and reverse reactions are equal

2. temperature change, concentration change of products and reactants, volum eof the vessel can change the value of an equilibirum constant

3. Kc = [NO₂]² / [N₂O₄]

4. The equilibrium constant depends on the quanties of reactants and products intially present