Question

Determine the temperature at the center of the rod using the heisler chart?

Can you show the work on how they got theata to 0.075

plane wall, long cylinder, and sphere were presented by M. P. in and are called Heisler charts. They were supplemented in 1961 with transient Heisler 194 -T 0.1 0.04 0.02 001 0.005 0.004 0 23 46310 14 18 22 26 30 50 70 100 120 150 300 400 500 600 700 Inially Тут, (a) Midplane temperatune From M.P.Heisler "Tmperature Chants for Induction and Consant Tempere Heanng Tuns. ASME 69、1947. pp. 227-36. Reprised by permission of ASME International T-T. 1.0 0.9 0.9 Bi hLA 0.7 0.6 0.5 0.4 0.7 0.6 0.1 Plate 1.0 10 100 10 10 10 (c) Heat transfer Froam H. Grober et al Pron M.P. Heisler "Tmperature Charts for lndaction and Consaut Temperanure Heating ns.ASME 6%, 1947, pp 227-36. Reprised

Answer 1

For the given values of 1/Bi = 10 & t = 13.61, the value of theta will not be 0.075 as per the figure. If you will interpolate the figure for the given values, you will get theta = 0.27. Which is much far than 0.075.

Also you can verify by interpolating horizontal line and check for its intersection with (1/Bi = 10), you can see that the intersection point will interpolate for t > 26.

This the correct value will be 0.27