Question

13 of 10 pt A glider is gliding in a horizontal circle at a speed of 35 m/s. If the glider is tilted 25° to the horizontal, what is the radius of the circle (in m) in which it is flying? (See the figure.) Assume that the required force is provided entirely by an 'aerodynamic lift' that is perpendicular to the wing surface. (in m) 4, AO 1.96 × 102 BO 2.29 × 102 2.68 × 102 DO 3.14 x 102 EO 3.67 x 10 FO 4.29 x 10 GO 5.02 x 10 HO 5.88 x 102 10 pt A bicycle is moving at a speed v 4.24 m/s. If the radius of the front wheel is 0.450 m, how long does it take for that wheel to make a complete revolution? (in s) 5. AO 2.22x 10-1 BO 2.60 × 10-1 CO 3.04 × 10-1 EO 4.16 x 101 FO 4.87 x 10-1 DO 3.56 x 10

Answer 1

The force balance equation is

So, the equation for the radius is,

$r = \frac{v^{2}}{g tan\theta }$

given,

v = 35 m/s

   $\theta$ = 25 degree

g is acceleration due to gravity and g = 9.8 m/s².

So,

$r = \frac{35^{2}}{9.8 \times tan25^{\circ}}$

or,    $r = 268.06 m = 2.68 \times 10^{2} m$

(5)

radius of the wheel = 0.450m

So, the circumference of the wheel = 2 x pi x 0.450 = 2.8274 m

Speed of the wheel = 4.24 m/s

So, time taken by wheel in complete revolution is

= 2.8274 / 4.24 = 6.67 x 10^-1 s