X | Y | (x-x̅)² | (y-ȳ)² | (x-x̅)(y-ȳ) |
68 | 90 | 1.235 | 16.901 | -4.568 |
72 | 85 | 8.346 | 0.790 | -2.568 |
65 | 88 | 16.901 | 4.457 | -8.679 |
70 | 100 | 0.790 | 199.123 | 12.543 |
62 | 105 | 50.57 | 365.235 | -135.90 |
75 | 98 | 34.68 | 146.679 | 71.32 |
78 | 70 | 79.01 | 252.457 | -141.23 |
64 | 65 | 26.1235 | 436.3457 | 106.7654 |
68 | 72 | 1.235 | 192.901 | 15.432 |
ΣX | ΣY | Σ(x-x̅)² | Σ(y-ȳ)² | Σ(x-x̅)(y-ȳ) | |
total sum | 622 | 773 | 218.889 | 1614.89 | -86.889 |
mean | 69.11 | 85.89 | SSxx | SSyy | SSxy |
a)
correlation coefficient , r = Sxy/√(Sx.Sy) = -0.1461
b)
sample size , n =
9
here, x̅ = Σx / n=
69.11
, ȳ = Σy/n
= 85.89
SSxx = Σ(x-x̅)² = 218.8889
SSxy= Σ(x-x̅)(y-ȳ) = -86.9
estimated slope , ß1 = SSxy/SSxx = -86.9
/ 218.889 = -0.3970
intercept, ß0 = y̅-ß1* x̄ =
113.3228
so, regression line is Ŷ =
113.3228 + -0.3970
*x
1. In the table below the height, x, in inches and the pulse r minute, for...
Use the accompanying data set on the pulse rates (in beats per minute) of males to complete parts (a) and (b) below. LOADING... Click the icon to view the pulse rates of males. a. Find the mean and standard deviation, and verify that the pulse rates have a distribution that is roughly normal. The mean of the pulse rates is 71.871.8 beats per minute. (Round to one decimal place as needed.) The standard deviation of the pulse rates is 12.212.2...
a sample of 41 minutes of pain in their height and inches and pulse rate in beats per minute are measured the linear correlation coefficient is 0.203 and the equation of the regression line is y equals 17.7 + 0.860 x where X represents height the mean of the 40 Heights is 62.9 in in the mean of the 40 pulse rate is 73.4 beats per minute find the best predicted pulse rate of a woman who is 72 in...
The data below shows height (in inches) and pulse rates (in beats per minute) of a random sample of women. Answer parts a-c. height (x) 62.962.9 64.164.1 60.360.3 60.860.8 59.459.4 62.762.7 59.859.8 62.662.6 67.867.8 60.260.2 67.667.6 63.563.5 pulse rate (y) 7676 7070 8686 6060 7474 6666 8181 6262 6767 6868 8282 7979 Click here to view a table of critical values for the correlation coefficient. LOADING... a. Find the value of the linear correlation coefficient r. requals=nothing (Round to three...
Listed below are pulse rates? (beats per? minute) from samples of adult males and females. Does there appear to be a? difference? Find the coefficient of variation for each of the two? samples; then compare the variation. Male 90 71 64 72 72 53 65 52 84 69 64 60 96 54 62 Female 64 83 79 70 74 84 87 85 89 89 92 69 88 80 80 The coefficient of variation for the male pulse is ____ %...
Listed below are pulse rates (beats per minute) from samples of adult males and females. Does there appear to be a difference? Find the coefficient of variation for each of the two samples; then compare the variation. Male 89 70 63 70 71 50 62 53 83 69 62 64 98 56 66 Female 67 82 79 72 72 82 86 85 89 87 93 70 90 80 80
Problem #1: Consider the below matrix A, which you can copy and paste directly into Matlab. The matrix contains 3 columns. The first column consists of Test #1 marks, the second column is Test # 2 marks, and the third column is final exam marks for a large linear algebra course. Each row represents a particular student.A = [36 45 75 81 59 73 77 73 73 65 72 78 65 55 83 73 57 78 84 31 60 83...
Listed below are pulse rates (beats per minute) from samples of adult males and females. Does there appear to be a difference? Find the coefficient of variation for each of the two samples; ther compare the variation. Male 90 72 60 70 71 53 62 52 82 70 63 64 98 58 65 Female 65 84 81 69 73 83 89 87 88 89 92 71 90 79 79 The coefficient of variation for the male pulse rates is 1...
A sample of 70 women is obtained, and their heights (in inches) and pulse rates (in beats per minute) are measured. The linear correlation coefficient is 0.259 and the equation of the regression line is , where x represents height. The mean of the 70 heights is 63.5 in and the mean of 70 pulse rates is 75.1 beats per minute. Find the best predicted pulse rate of a woman who is 67 in tall. Use a significance level of...
A sample of 80 women is obtained, and their heights (in inches) and pulse rates (in beats per minute) are measured. The linear correlation coefficient is 0.218 and the equation of the regression line is ŷ=17.9+0.950x, where x represents height. The mean of the 80 heights is 63.3 in and the mean of the 80 pulse rates is 73.5 beats per minute. Find the best predicted pulse rate of a woman who is 72 in tall. Use a significance level...
26 students took an exam. Their scores are below: 64 65 69 62 72 94 86 68 72 85 66 96 91 86 97 62 68 84 76 98 65 70 75 64 72 70 The 30th percentile is the closest to: 70 68 85 80 66 CE a o te hp