show excel steps please A particular fruit's weights are normally distributed, with a mean of 527...

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Question

show excel steps please
A particular fruits weights are normally distributed, with a mean of 527 grams and a standard deviation of 7 grams. If you p

Answer 1

Answer #1

Solution :

Given that ,

mean = $\mu$ = 527

standard deviation = $\sigma$ = 7

P(527< x <549 ) = P[(527-527]/7 < (x - $\mu$ ) / $\sigma$ < (549-527) /7 )]

= P(0 < Z <3.14 )

= P(Z <3.14 ) - P(Z <0 )

Using z table

= 0.9992-0.5

probability=0.4992

Answer 2

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