Given 25 ml of a KCl solution with a concentration of 0.38 M and 18 ml of a solution of CaCl2 with a concentration of 0.19 M, what amount of each solution you should use to make 40 ml of solution with [Cl-]=0.30 M ?
KCl solution:
Using the releation: M * V = constant
Volume of KCl needed * Molarity of KCl = Volume of Cl- solution * molarity
V * 0.38 = 40 * 0.3
Solving, we get: V = 10.53 ml
CaCl2 Solution:
Since each CaCl2 has 2 chloride ions, the relation is:
2 * Volume of CaCl2 needed * Molarity of CaCl2 = Volume of Cl- solution * molarity
2 * V * 0.38 = 40 * 0.30
Solving, we get: V = 5.26 mL
Given 25 ml of a KCl solution with a concentration of 0.38 M and 18 ml...
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