Question

6. How many mL of a 0.250 M KCl solution contains 34.5 g KCI? 7. To what volume (in mL) should you dilute 100.0 mL of a 2.50 M CaCl2 solution to obtain a 0.550 M CaCl2 solution?

Answer 1

6) Solution volume is calculated:

V = 34.5 g KCl * (1 mol KCl / 74.6 g) * (1000 mL solution / 0.25 mol) = 1850 mL

7) The final volume is calculated:

V2 = C1 * V1 / C2 = 2.50 M * 100 mL / 0.550 M = 454.5 mL

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