Question

50 mL of 0.38 M LiNO3 is diluted to 5.0 L. what is the concentration of the new solution?

Answer 1

Here, initial concentration (M1) is 0.38 M, initial volume (V1) is 50 mL = 0.05 L and final volume (V2) is 5L. The final concentration (M2) can be calculated by using following formula,

M1 x V1 = M2 x V2

Rearranging the above equation for M2, we get

M2 = (M1 x V1) / V2

= (0.38 x 0.05) / 5 = 0.0038 M

Therefore, the concentration will be 0.0038 M.