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An unpolorized light with intensity i0 is incident on two polorizing filter. The axis of the first filter makes an angle of 40 with the verticla and the axis of the secons filter is horizontal. What is the intensity of the light after it has passed through the second filter?
Homework Answers
here,
initial intensity of light is i0
theta = 40 degree
when light passes through first polarizer , i1 = 0.5 * i0
when the light is passed throught the seccond polarizer , i2 = i1 * ( cos(phi))^2
i2 = 0.5 * i0 * ( cos(90 - theta))^2
i2 = 0.5 * i0 * ( cos(90 - 40))^2
i2 = 0.21 * i0
the intensity of light passed through the seccond polarizer is 0.21 * i0
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5) Please Help
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Helppppp
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Please show your work on how it is done. thank you!
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