Question

2. An unpolarized beam of light with intensity lo = 98.8 lux is incident on three ideal polarizing filters (lux = ). The axis of the first filter (filter A) makes an angle of 18° with the vertical and the axis of the second filter (filter B) makes an angle of 37° with the vertical. The third filter (filter C) is oriented so that its axis is horizontal. a. What is the intensity and polarization direction of the light after it passes through the first filter? b. What is the intensity of the light after it passes through the first and second polarizing filters? c. What is the intensity of the light after it passes through all three polarizing filters? Note: Light passes polarizing filters in the following order A, B, and C. d. At what two angles, with respect to the vertical, would you need to orient the axis of filter C so that the intensity of the light after it passes all three filters is 0.0 lux? Note: Light passes polarizing filters in the following order A, B, and C.

Answer 1

Solution 4 b Incensity a light becomes 90 - 988 = 149.4 dur] Polarization direction is 180 from the vertica a ltor passing through first polaryzer intensity becomes I I. 49.4 lux. ongle between dinst & second polarizes 37 - 18 - 19 - hence intensity after pussing through second becomes Iz" . I 2 = I Cos²o 49.4 cos²ig. 144. 163 dun Since the polaru aer co horizontal then its angle from vertical will be goo s from BIB' 90-37 - 53

intensity of light after passing a becomes. I= I lost o' I = 2124, 163 Cas²3 I3 - 15.99 = 116 le di it polarizes will orient at go to A and & then all will get zero intensity hence ongles are on - 18+ 9o - (108) 5 = 37+90 = 1127°)