Question

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An unpolarized beam of light with intensity 10 = 98.8 lux is incident on three ideal polarizing filters (lux = ). The axis of the first filter (filter A) makes an angle of 18° with the vertical and the axis of the second filter (filter B) makes an angle of 37° with the vertical. The third filter (filter C) is oriented so that its axis is horizontal. a. What is the intensity and polarization direction of the light after it passes through the first filter? b. What is the intensity of the light after it passes through the first and second polarizing filters? c. What is the intensity of the light after it passes through all three polarizing filters? Note: Light passes polarizing filters in the following order A, B, and C. d. At what two angles, with respect to the vertical, would you need to orient the axis of filter C so that the intensity of the light after it passes all three filters is 0.0 lux? Note: Light passes polarizing filters in the following order A, B, and C.

Answer 1

The changing of intensity followes : I Io costo. where, I = Intensity before falling on I = Intensity ofter coming out filter o Orientation of filter wrot previous one. a. unpolarised, for Here & Io = 98.8 lux. As the light was unpolarisa this case only. I will be the average of To costo Il (I, Costo) 98.8 - 49.4 luxe. Orientation : Parallel to the optic l. I aseis of the filter sie. 180, with verticle. – I cos2 (37° - 180) 2 49.4. cost 19 = 44.16 lux. In a I cose (90° - 370) [as it's horizontal] 4.1.6 x cos 53° = 16 liex. c. Iz = d. To make the intensity o, the onentation should be , o I cosa coso - 0 2 0- 90°, 270°. e to orient the axis of a or 270° angle with respect 40 filter B. to no get intensity