Xianming runs a titration and collects, dries, and weighs the BaSO4(s) produced in the experiment. He reports a mass of 0.2989 g go BaSO4. Based on this, calculate the concentration of Ba(OH)2 solution. [Ba(OH)2] = ___ M
Xianming runs a titration and collects, dries, and weighs the BaSO4(s) produced in the experiment. He...
calculate the mass in grams of BaSo4 that was formed from the following information. Moles of Ba(OH)2 = Moles BaSo4 volume Ba(OH)2 dispensed = 10 ml Molarity of H2SO4 used = 0.100 M Molarity of Ba(OH)2 solution = 0.118 M
Please show all work !
Experiment 9 Conductometric Titration and Gravimetric Determination of a Precipitate REPORT SHEET Name: DATA TABLE Trial 1 Trial 2 Trial 3 Equivalence point (mL) 27.l16 mL Mass of filter paper precipitate ()311 I1133 20139 03228 Mass of filter paper (9) Mass of precipitate (g) Molarity of HaSO (M) DATA ANALYSIS (If you need more space, provide your answers on the back page) 1. Use the titration results to calculate the moles of H2SO4 that were...
In a titration experiment, 29.9 mL of 0.797 M HCOOH neutralizes 20.6 mL of Ba(OH)2. What is the concentration of the Ba(OH)2 solution?
EXPERIMENT 10 ACID AND BASE TITRATION 2 Post - Laboratory Questions 1. Student A weighs 0.747 g of KHP on a laboratory balance. The KHP was titrated with an unknown NaOH solution and the concentration of the NaOH was determined to be 0.113 M. Student B diluted 6 M HCl from the reagent shelf using a volumetric flask to obtain 0.6 MHCI. This solution was titrated with the same unknown NaOH solution and found to be 0.104 M. Which student...
A student weighs a sample of potassium hydrogen phthalate (KHP) to prepare a primary standard for a titration. She later discovers that the KHP was contaminated with sugar. To determine the amount of KHP in the mixture, she takes 5.942 g of the mixture and make a 100.0 mL solution. The student then titrates 10.00 mL of this solution with a 0.1491 M sodium hydroxide solution. She finds that 13.12 mL of the NaOH solution is needed to reach the...
Suppose a student needs to standardize a sodium thiosulfate, Na, S,Og, solution for a titration experiment. To do so, he or she will react it with a solution of iodine. The student adds a 1.00 mL aliquot of 0.0200 M KIO2 solution to a flask, followed by 3 mL of distilled water, 0.2 g of solid KI, and 1 mL H,SO,. The student then titrates the solution with sodium thiosulfate solution in order to determine the exact concentration of Na,...
Suppose a student needs to standardize a sodium thiosulfate, Na, S,O,, solution for a titration experiment. To do so, he or she will react it with a solution of iodine. The student adds a 1.00 mL aliquot of 0.0200 M KIO, solution to a flask, followed by 3 mL of distilled water, 0.2 g of solid KI, and I mL H, SO. The student then titrates the solution with sodium thiosulfate solution in order to determine the exact concentration of...
During a titration experiment, when you add 52.00mL of 0.98 M Ba(OH)2 to 42.00 mL of H3A to reach the equivalence point. What is the concentration of H3A? The MW of H3A = 69.0 g/mol
During a titration experiment, when you add 52.00mL of 0.98 M Ba(OH)2 to 42.00 mL of H3A to reach the equivalence point. What is the concentration of H3A? The MW of H3A = 69.0 g/mol
To calculate the concentration of a solution using acid–base titration data. In an acid–base titration, an acid (or base) of known concentration is added to a base (or acid) of unknown concentration until the number of moles of H+ and OH- are equal, a condition called the equivalence point. Since you know the number of moles of H+ (or OH- ) that you added, you can determine the number of moles of OH- (or H+) in the unknown solution. For...