first it change from gas to liquid ( phase change )
Q = Lvm = 879 * .567 = 498.4 kJ
now from 78 degree to -114 degree
Q = mcdT
Q = .567 * 2.43 * 192 K = 264.54 kJ
now again phase change from liquid to solid
Q = Lf*m
Q = 109*0.567 = 61.803 kJ
total = 498.4 kJ + 264.54 kJ + 61.803
total energy removed = 824.74 kJ
Ethyl alcohol has a boiling point of 78.0 degree C, a freezing point of -114 degree...
Ethyl alcohol has a boiling point of 78.0 ˚C, a freezing point of -114 ˚C, a heat of vaporization of 879 kJ/kg, a heat of fusion of 109 kJ/kg, and a specific heat of 2.43 kJ/kg·K. How much energy must be removed from 0.689 kg of ethyl alcohol that is initially a gas at 78.0 ˚C so that it becomes a solid at -114 ˚C?
Ethyl alcohol has a boiling point of 78.0 ˚C, a freezing point of -114 ˚C, a heat of vaporization of 879 kJ/kg, a heat of fusion of 109 kJ/kg, and a specific heat of 2.43 kJ/kg·K. How much energy must be removed from 0.683 kg of ethyl alcohol that is initially a gas at 78.0 ˚C so that it becomes a solid at -114 ˚C?
Ethyl alcohol has a boiling point of 78.0 degrees Celsius, a freezing point of -114 degrees Celsius, a latent heat of vaporization of 879 kJ/K, a latent heat of fusion of 109 kJ/K, and a specific heat of 2.43 kJ/kg.K. How much energy must be removed from 0.510 kg of ethyl alcohol that is initially a gas at 78.0 degrees Celsius so that it becomes a solid at -114 degrees Celsius?
Chapter 18, Problem 039 Ethyl alcohol has a boiling point of 78.0 °C, a freezing point of -114 °C, a heat of vaporization of 879 kJ/kg, a heat of fusion of 109 kJ/kg, and a specific heat of 2.43 kJ/kg K. How much energy must be removed from 0.765 kg of ethyl alcohol that is initially a gas at 78.0 °C so that it becomes a solid at -114 C? Number Units the tolerance is +/-2%
Question 5 Ethyl alcohol has a boiling point of 78.0 °C, a freezing point of -114 °c, a heat of vaporization of 879 kJ/kg, a heat of fusion of 109 kJ/kg, and a specific heat of 2.43 kJ/kg-K. How much energy must be removed from 0.539 kg of ethyl alcohol that is initially a gas at 78.0 °C so that it becomes a solid at -114 °C? Number Units the tolerance is +/-2% This answer has no units SAVE FOR...
Need help on those two problems! Question 4 Incorrect. Ethyl alcohol has a bolling point of 780°C a freezing point of-1 14 С a heat of vaporization of 879 kJkg a heat of fusion of 109 kle and a specific C? Number778 heat of 243kJkgK. Howmuch enersy must be removed from Os535 kg of ethylalcoho that sinitialy gas at 780 C so that i becomes a sold a 114 Units kg eTextbook and Media Hint Attempts: 1 of 6 used...
What is the freezing point of an alcohol in °C to the nearest degree if its heat of fusion(AHlusº) +9.37 kJ/mol and its entropy of fusion ASfusº = 50.6 J/K.mol.
potassium metal has melting point of 63.65 C and a boiling point of 774 C Enthalpy fusion = 14.37 cal/g enthaply of vaporization = 490.3 cal/g Specific heat @ solid = .1759 cal/gC specfic heat @ liquid =.5425 cal /gC specfic heat @ gas = .2629 cal /gC a) draw heatung curve that us heated from 23C to 1200c b) Calculate total heat required in units of kJ for 39.5 g of potassium
Methylene chloride has a melting point of - 94.8°C, a boiling point of 40.0°C, a specific heat of 1.21 J/g *K for the solid and liquid, and 0.608 J/g*K for the gas. The heats of fusion and vaporization are ΔHfus of 73.40 J/g, and ΔHvap of 334.35 J/g respectively. Determine how many joules of energy are needed to heat 40 grams of methylene chloride from -171.4 ° F to 333 K. Draw out and label your heating curve. This will...
How much heat energy is required to convert 82.0 g of solid ethanol at -114.5 degree C to gaseous ethanol at 167.4 degree C? The molar heat of fusion of ethanol is 4.60 kJ/mol and its molar heat of vaporization is 38.56 kJ/mol. Ethanol has a normal melting point of -114.5 degree C and a normal boiling point of 78.4 degree C. The specific heat capacity of liquid ethanol is 2.45 J/g middot degree C and that of gaseous ethanol...