Homework Answers
we have:
T1 = 30 oC
=(30+273)K
= 303 K
T2 = 50 oC
=(50+273)K
= 323 K
K1 = 5.2*10^3
K2 = 1.54*10^5
we have below equation to be used:
ln(K2/K1) = (Ea/R)*(1/T1 - 1/T2)
ln(1.54*10^5/5.2*10^3) = ( Ea/8.314)*(1/303.0 - 1/323.0)
3.3883 = (Ea/8.314)*(2.044*10^-4)
Ea = 137850 J/mol
Ea = 137.8 KJ/mol
Answer: 137.8 KJ/mol
Feel free to comment below if you have any doubts or if this answer do not work. I will edit it if you let me know
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