Using the reduction potentials given, calculate the equilibrium constant, K, at 20 degrees C for the reaction
Using the reduction potentials given, calculate the equilibrium constant, K, at 20 degrees C for the reaction Using the reduction potentials given, calculate the equilibrium constant, K, at 25°C for...
Cell Potential and Equilibrium Standard reduction potentials The equilibrium constant, K, for a redox reaction is related to the standard cell potential, Ecel, by the equation Reduction half-reaction (V) Ag+ (aq) + e-→Ag(s) Cu2+ (aq) + 2e-→Cu(s) 0.34 Sn (a) 4e-Sn(s 0.15 2H' (aq) + 2e-→H2 (g) Ni2+ (aq) + 2e-→Ni(s)-0.26 Fe2+ (aq) + 2e-→Fe(s)-0.45 Zn2+ (aq) + 2e-→Zn(s)-0.76 Al3+ (aq) +3e-→Al(s) -1.66 Mg2+ (aq) + 2e-→Mg(s) -2.37 0.80 n FEcell where n is the number of moles of electrons...
The equilibrium constant, K, for a redox reaction is related to the standard potential, Eº, by the equation In K = nFE° RT where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e), R (the gas constant) is equal to 8.314 J/(mol · K), and T is the Kelvin temperature. Standard reduction potentials Reduction half-reaction E° (V) Ag+ (aq) + e +Ag(s) 0.80 Cu²+ (aq) + 2e + Cu(s) 0.34...
tandard reduction half-cell potentials at 25 ∘ C Half-reaction E ∘ ( V ) Half-reaction E ∘ ( V ) A u 3+ (aq)+3 e − →Au(s) 1.50 F e 2+ (aq)+2 e − →Fe(s) − 0.45 A g + (aq)+ e − →Ag(s) 0.80 C r 3+ (aq)+ e − →C r 2+ (aq) − 0.50 F e 3+ (aq)+3 e − →F e 2+ (aq) 0.77 C r 3+ (aq)+3 e − →Cr(s) − 0.73 C u +...
Standard reduction half-cell potentials at 25°C E (V) E (V) 1.50 -0.45 0.80 -0.50 0.77 -0.73 0.52 -0.76 0.34 -1.18 Half-reaction Aut (aq) + 3e +Au(s) Ag+ (aq) + +Ag(s) Fe3+ (aq) +34 Fo+ (aq) Cut(aq) + Cu(s) Cu²+ (aq) + 2e +Cu(s) 2H+ (aq) - 2e +H2 (6) Fe3+ (aq) + 3e Fe(s) Pb2+ (aq) + 2e →Pb(s) Sn-(aq) + 2e +Sn(s) Ni2+ (aq) + 2e →Ni(s) Co2(aq) +2e + Co(s) ca? (aq) + 2e +Cd(s) 0.00 Half-reaction Fe(aq)...
4. (a) Use the standard reduction potentials at 25° C in Table 18.1 in Tro, Fridgen and Shaw, and calculate the standard emf E° of an electrochemical cell described by the following reaction: 3 Zn + 2 Cr3+ + 2 Cr + 3 Zn? (b) What is n? (c) What is AGº for this reaction at 25°? (d) What is the equilibrium constant for this reaction at 25°? TABLE 18.1 Standard Reduction Potentials at 25°C EV) 2.87 1.61 1.51 1.36...
Use standard reduction potentials to calculate the equilibrium constant for the reaction: Fe(a 2Fe(a) Fe(s)+2Fe (aq) Hint: Carry at least Equilibrium constant: than zero. AO for this reaction would be 9 more group a Submit Answer Retry Entire Group ing Use standard reduction potentials to calculate the equilibrium constant for the reaction: Sn2+(aq) + Fe(s)-→ Sn(s) + Fe2+(aq) Hint: Carry at least S significant figures during intermediate calculations to avoid round off error when taking the antilogarithnm. Equilibrium constant AG°...
Use the tabulated electrode potentials to calculate K for the oxidation of nickel by H+: Ni(s)+2H+(aq)→Ni2+(aq)+H2(g) Express your answer using two significant figures. Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V) Half-reaction E∘ (V) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) −0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) −0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) −0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) −0.76 Cu2+(aq)+2e−→Cu(s) 0.34 Mn2+(aq)+2e−→Mn(s) −1.18 2H+(aq)+2e−→H2(g) 0.00 Al3+(aq)+3e−→Al(s) −1.66 Fe3+(aq)+3e−→Fe(s) −0.036 Mg2+(aq)+2e−→Mg(s) −2.37 Pb2+(aq)+2e−→Pb(s) −0.13 Na+(aq)+e−→Na(s) −2.71 Sn2+(aq)+2e−→Sn(s) −0.14 Ca2+(aq)+2e−→Ca(s) −2.76 Ni2+(aq)+2e−→Ni(s) −0.23 Ba2+(aq)+2e−→Ba(s) −2.90 Co2+(aq)+2e−→Co(s) −0.28 K+(aq)+e−→K(s) −2.92 Cd2+(aq)+2e−→Cd(s)...
Use standard reduction potentials to calculate the equilibrium constant for the reaction: 2Cu2 (aq)+ Fe(s)-2Cu (aq)+ Fe2 (aq) Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant: AG° for this reaction would be than zero.
Use the appropriate standard reduction potentials in the hint to calculate the value of K at 25 degree C for the reaction: 5Fe^2+ (aq) + MnO_4^- (aq) + 8H^+ (aq) rightarrow 5Fe^3+ (aq) + Mn^2+ (aq) + 4H_2O(l) K = The two half-reactions are: MnO_4^- (s) + 8H^+ (aq) + 5e^- rightarrow Mn^2+ (aq) + 4H_2O(l) E degree = 1.507V Fe^3+ (aq) + e^- rightarrow Fe^2+ (aq) E degree = 0.770V What equation relates standard reduction potentials (E degree _cell)...
Review I Constants I Periodic Table The equilibrium constant, K, for a redox reaction is related to the standard potential, E°, by the equation Standard reduction potentials nFE RT In K E° (V) Reduction half-reaction Agt(aq)eAg(s) Cu2+(aq)2eCu(s) 0.80 where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e), R (the gas constant) is equal to 8.314 J/(mol - K) , and T is the Kelvin temperature. 0.34 Sn4t (aq)4eSn(s) 0.15...