![Problem # 3: Induction Motor Analysis [30 points] The parameters of the per phase equivalent circuit of a three phase wye-connected, 220 V (line- line, rms) 10 hp, 60 Hz, six-pole induction motor are given as: Ri = 0.3 Ohm, R2-0.15 Ohm, Xi-0.5 Ohms, X2= 0.2 Ohm, Xm-15.0 The total friction, windage and core losses add up to be a constant of 400 W. For a slip of 0.025 with motor operating at rated frequency and stator voltage, calculate the followings: (1) The stator input current and input power factor [12 points) (2) The output shaft power and efficiency [12 points] (3) The ratio of the developed torque to the output shaft torque [6 points]](http://img.homeworklib.com/questions/5fac52c0-7d3c-11eb-9d05-3f8a0baf5765.png?x-oss-process=image/resize,w_560)
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Problem # 3: Induction Motor Analysis [30 points] The parameters of the per phase equivalent circuit...
The input power to a 480V, 3 phase, 6 pole, 50 Hz induction motor is 75kW...
The input power to a 480V, 3 phase, 6 pole, 50 Hz induction motor is 75kW with a line current of 75A and runs at a slip of 2.5%. If the stator core loss is 2 kW, windage and friction loss is 1.2 kW, and the stator resistance per phase is 0.16 ohm. Calculate: a. Power supplied to the rotor (Air gap power) b. Rotor copper loss c. Shaft power d. Efficiency of the motor e. Shaft torque f What...
A three-phase 4 pole wye connected 220 V, 15 Hp, 50 Hz induction machine (rated conditions) has t...
A three-phase 4 pole wye connected 220 V, 15 Hp, 50 Hz induction machine (rated conditions) has the following parameters per phase refereed to the stator. RI : 0.29 Ω , R2 0. 14 Ω , Xi-0.50 Ω , X2-0.20 Ω , Xm-1 0.53 Ω The total windage and core losses can be assumed to be a constant 350 W. If the machine is operating at rated voltage and frequency with a 5.5% slip, find the steady-state: (a) 10pts. Mechanical...
I want to solve this problem step by step. Thanks (35 points) Induction Generator Real Power Generation. A three phase, 220V line to line, six pole, 60Hz, wye connected induction machine op...
I want to solve this problem step by step. Thanks
(35 points) Induction Generator Real Power Generation. A three phase, 220V line to line, six pole, 60Hz, wye connected induction machine operates at rated voltage as a generator at a slip of-0.04. Its equivalent circuit parameters are the same as those in problem #1. The input mechanical power at the rotor (this is a generatorl) is 5.2kW. The core losses are 200Watts; friction and windage losses are 17 Watts; treat...
Problem # 2: Induction Motor Analysis Using The Thevenin Theorem [37 points] A three-phase, two p...
Problem # 2: Induction Motor Analysis Using The Thevenin Theorem [37 points] A three-phase, two pole, 25hp, 460V (line-line), 60Hz, wye-connected, squirrel-cage induction motor has the following per-phase parameters: Ri 0.53 Ohm X2 0.80 Ohm Xi 1.80 Ohms R2 0.30 Ohm Re- 400 Ohms Xm 25.0 Ohms You cannot use any approximate circ uit or any approximation in the calculations. (1) Determine the parameters of the Thevenin equivalent circuit. Draw the equivalent circuit with the appropriate parameter values indicated on...
Problem 2. (25 points) For a 120-V, 1/3 hp, four pole, 1-phase induction motor, the parameters of the equivalent circuit, are R,-1.8(2, R,-2.5Ω, X,-X,-2.462, and Xm-60 Ω. At a slip of 500, the motor&...
Problem 2. (25 points) For a 120-V, 1/3 hp, four pole, 1-phase induction motor, the parameters of the equivalent circuit, are R,-1.8(2, R,-2.5Ω, X,-X,-2.462, and Xm-60 Ω. At a slip of 500, the motor's rotational losses are 51W. The rotational losses maybe assumed constant over the normal operating range of the motor. If the slip is 0.05, calculate a. Input Power b. Air Gap Power, c. Induced Torque Tin d. Output power e. Load torque. f. Overall Motor efficiency g....
A 3 phase, 460V, 60Hz, 6-pole induction motor has the following equivalent circuit parameters per phase:...
A 3 phase, 460V, 60Hz, 6-pole induction motor has the following equivalent circuit parameters per phase: R1 = 0.2 ohms R2 = 0.28 ohms X1 = X2 = 1.055 ohms Xm = 33.9 ohms The no load losses, comprising friction, windage, and iron losses equal 26W. The motor is coupled to a load and connected to a 460V supply, and the rotor speed is found to be 1156 RPM. For this motor connected to a 460V supply calculate the following:...
A four-pole Y-connected, 415 V, 50 Hz, induction motor has phase equivalent circuit parameters of R1=...
A four-pole Y-connected, 415 V, 50 Hz, induction motor has phase equivalent circuit parameters of R1= 2 ohms. R2=2.2 ohms. X1=X2=4 ohms. X(motor)=90 ohms Under rated condition, the rotor slip is 6%. (i) What is the rotor speed and rotor electrical frequency under the rated conditions; (ii) Calculate the stator input current, power factor, and electromagnetic torque under these conditions; (iii) The machine is running at rated conditions and it is to be stopped by switching the two stator leads....
A 4 phase, 460 V, 60 Hz, 26.8 hp, 4 pole, Y-connected induction motor draws 25...
A 4 phase, 460 V, 60 Hz, 26.8 hp, 4 pole, Y-connected
induction motor draws 25 A at a power factor of 0.9 lagging. Core
loss is 900 W, stator copper loss is 1100W, friction and winding
losses are 300 W, and stray loss is neglected. The machine shaft
rotates at 1738 rpm. Calculate the air gap power and output load
torque
- [Induction Motor - 15 points) A three-phase, 460 V, 60 Hz, 26.8 hp, 4-pole, Y-connected induction motor...
6.12 A three-phase, Y-connected, 460-V (line-line), 37-kW, 60-Hz, four-pole induction motor has the following equivalent-circuit parameters...
6.12 A three-phase, Y-connected, 460-V (line-line), 37-kW, 60-Hz, four-pole induction motor has the following equivalent-circuit parameters in ohms-per-phase referred to the statr: R10.070 R2 0.152 X 0.743 X2 0.764 Xm 40.1 The total friction and windage losses may be assumed constant at 390 W, and the core loss may be assumed to be equal to 325 W. With the motor connected directly to a 460-V source, compute the speed, output shaft torque and power, input power, and power factor and...
. A 460-V 460-V, 25-hp, 60-Hz, six-pole, Y-connected induction motor has the following impedanc ohms per...
. A 460-V 460-V, 25-hp, 60-Hz, six-pole, Y-connected induction motor has the following impedanc ohms per phase referred to the stator circuit. Ri= 0.212 R2 = 0.282 X1 = 1.055 12 X2 = 1.055 22 XM = 33.9 W The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped with the rotational losses. For a rotor slip of 4% at the rated voltage and rated frequency, a) The input power b) Peony...
A three-phase 4 pole wye connected 220 V, 15 Hp, 50 Hz induction machine (rated conditions) has the following parameters per phase refereed to the stator. RI : 0.29 Ω , R2 0. 14 Ω , Xi-0.50 Ω , X2-0.20 Ω , Xm-1 0.53 Ω The total windage and core losses can be assumed to be a constant 350 W. If the machine is operating at rated voltage and frequency with a 5.5% slip, find the steady-state: (a) 10pts. Mechanical...
I want to solve this problem step by step. Thanks
(35 points) Induction Generator Real Power Generation. A three phase, 220V line to line, six pole, 60Hz, wye connected induction machine operates at rated voltage as a generator at a slip of-0.04. Its equivalent circuit parameters are the same as those in problem #1. The input mechanical power at the rotor (this is a generatorl) is 5.2kW. The core losses are 200Watts; friction and windage losses are 17 Watts; treat...
Problem # 2: Induction Motor Analysis Using The Thevenin Theorem [37 points] A three-phase, two pole, 25hp, 460V (line-line), 60Hz, wye-connected, squirrel-cage induction motor has the following per-phase parameters: Ri 0.53 Ohm X2 0.80 Ohm Xi 1.80 Ohms R2 0.30 Ohm Re- 400 Ohms Xm 25.0 Ohms You cannot use any approximate circ uit or any approximation in the calculations. (1) Determine the parameters of the Thevenin equivalent circuit. Draw the equivalent circuit with the appropriate parameter values indicated on...
Problem 2. (25 points) For a 120-V, 1/3 hp, four pole, 1-phase induction motor, the parameters of the equivalent circuit, are R,-1.8(2, R,-2.5Ω, X,-X,-2.462, and Xm-60 Ω. At a slip of 500, the motor's rotational losses are 51W. The rotational losses maybe assumed constant over the normal operating range of the motor. If the slip is 0.05, calculate a. Input Power b. Air Gap Power, c. Induced Torque Tin d. Output power e. Load torque. f. Overall Motor efficiency g....
A 4 phase, 460 V, 60 Hz, 26.8 hp, 4 pole, Y-connected
induction motor draws 25 A at a power factor of 0.9 lagging. Core
loss is 900 W, stator copper loss is 1100W, friction and winding
losses are 300 W, and stray loss is neglected. The machine shaft
rotates at 1738 rpm. Calculate the air gap power and output load
torque
- [Induction Motor - 15 points) A three-phase, 460 V, 60 Hz, 26.8 hp, 4-pole, Y-connected induction motor...
6.12 A three-phase, Y-connected, 460-V (line-line), 37-kW, 60-Hz, four-pole induction motor has the following equivalent-circuit parameters in ohms-per-phase referred to the statr: R10.070 R2 0.152 X 0.743 X2 0.764 Xm 40.1 The total friction and windage losses may be assumed constant at 390 W, and the core loss may be assumed to be equal to 325 W. With the motor connected directly to a 460-V source, compute the speed, output shaft torque and power, input power, and power factor and...
. A 460-V 460-V, 25-hp, 60-Hz, six-pole, Y-connected induction motor has the following impedanc ohms per phase referred to the stator circuit. Ri= 0.212 R2 = 0.282 X1 = 1.055 12 X2 = 1.055 22 XM = 33.9 W The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped with the rotational losses. For a rotor slip of 4% at the rated voltage and rated frequency, a) The input power b) Peony...
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