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Problem 2. (25 points) For a 120-V, 1/3 hp, four pole, 1-phase induction motor, the parameters of the equivalent circuit, are R,-1.8(2, R,-2.5Ω, X,-X,-2.462, and Xm-60 Ω. At a slip of 500, the motor&...
A 3-phase, 208 V, 60 Hz, 30 hp, four-pole induction motor
A 3-phase, 208 V, 60 Hz, 30 hp, four-pole induction motor has the following equivalent circuit parameters. R1 = 0.2 Ω, , , Xm = 12Ω.The rotational loss is 500 W. For a slip of 5%, calculate (a) The motor speed in rpm and radians per sec (b) The current drawn by the motor from the power supply (c) The stator cu-loss (d) The air gap power (e) The rotor cu-loss (f) The shaft power (g)The developed torque and the shaft torque (h) The efficiency of the motor Use...
A 480 V, 60 Hz, 4-pole-pair, three-phase, delta-connected induction motor has the following parameters: R1=0.42 Ω,...
A 480 V, 60 Hz, 4-pole-pair, three-phase, delta-connected induction motor has the following parameters: R1=0.42 Ω, R2=0.23 Ω, X1=0.48 Ω, X2=0.29 Ω, Xm=29.71 Ω where: R1 is the stator resistance R2 is the rotor resistance reflected in the stator; X1 is the stator leakage inductance; X2 is the rotor leakage inductance reflected in the stator; Xm is the magnetising inductance; The rotational losses are 2450 W. The motor drives a mechanical load at a speed of...
. A 460-V 460-V, 25-hp, 60-Hz, six-pole, Y-connected induction motor has the following impedanc ohms per...
. A 460-V 460-V, 25-hp, 60-Hz, six-pole, Y-connected induction motor has the following impedanc ohms per phase referred to the stator circuit. Ri= 0.212 R2 = 0.282 X1 = 1.055 12 X2 = 1.055 22 XM = 33.9 W The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped with the rotational losses. For a rotor slip of 4% at the rated voltage and rated frequency, a) The input power b) Peony...
Problem # 3: Induction Motor Analysis [30 points] The parameters of the per phase equivalent circuit...
Problem # 3: Induction Motor Analysis [30 points] The parameters of the per phase equivalent circuit of a three phase wye-connected, 220 V (line- line, rms) 10 hp, 60 Hz, six-pole induction motor are given as: Ri = 0.3 Ohm, R2-0.15 Ohm, Xi-0.5 Ohms, X2= 0.2 Ohm, Xm-15.0 The total friction, windage and core losses add up to be a constant of 400 W. For a slip of 0.025 with motor operating at rated frequency and stator voltage, calculate the...
A three-phase, six-pole 440 V, 60 Hz induction motor has the following per-phase equivalent circuit parameters...
A three-phase, six-pole 440 V, 60 Hz induction motor has the following per-phase equivalent circuit parameters referred to the stator: R1 = negligible, R’2 =0.3 Ω, Rφ = infinite, X1 = 1.131 Ω, X’2 = 1.131 Ω and Xφ = 37.7 Ω. Rotational losses are negligible. Assume the stator is connected to a 440 V, 60 Hz source and use the 6-parameters IEEE model. a) Determine the motor starting torque. (5 points) b) Calculate the motor breakdown torque. (5 points)...
A 230 V, 50 Hz, three-phase, Y-connected, 6-pole induction motor has the following per-phase parameters R-0.07...
A 230 V, 50 Hz, three-phase, Y-connected, 6-pole induction motor has the following per-phase parameters R-0.07 Ro 00 0.08 Ω x, x, 0.3 xm 6.33 At a slip of 2%, determine the followings using approximate equivalent circuit of the motor i) The motor speed in rev/min and rad/s. ii) The rotor current. ii) The stator current. iv) The induced torque. v) The efficiency of the motor.
A two-pole, 75kW, 440 V, 50 Hz, Y-connected, three-phase squirrel cage induction motor has the fo...
Please solve this question. Thank you.
A two-pole, 75kW, 440 V, 50 Hz, Y-connected, three-phase squirrel cage induction motor has the following parameters, in Ω/phase referred to the stator: R1-0.075, XI 0.17, xm-72, R2-0.065 and X-0.17. Its rated slip is 4%. Assume that the mechanical losses are 1 kW and the core losses are 1.1 kW. Compute: a. The rated input current b. The rated power factor. c. The pullout torque d. The induced and load torques at rated conditions....
1. A 15 hp, 4 pole, 208 V, 60 Hz, Y-connected, three-phase squirrel cage induction motor has the ...
1. A 15 hp, 4 pole, 208 V, 60 Hz, Y-connected, three-phase squirrel cage induction motor has the following parameters in Ω/phase referred to the stator: R,-0.220, Xi = 0.430, X,-15.0, R2 0.130 and X2-0.430. Mechanical and core losses amount to 300 W and 200 W respectively for rated voltage. (a) The motor is fed with a 60 Hz, 208 V voltage. It runs with a slip of 4.5 %. Find the speed, shaft torque and power, efficiency and power...
Name: 23. A 3-phase, 5000 hp, 6000 v,60 Hz, 12-pole wound-rotor induction motor has the 1, resistance between stator terminals-o12 Ω 2. resistance between rotor slip-rings-0.0073 Ω 3. windage and...
Name: 23. A 3-phase, 5000 hp, 6000 v,60 Hz, 12-pole wound-rotor induction motor has the 1, resistance between stator terminals-o12 Ω 2. resistance between rotor slip-rings-0.0073 Ω 3. windage and friction losses-51 kW following characteristics 4. iron losses in the stator-39 kW 5. locked rotor current at 6000 V-1800 A 6. active power to the stator with rotor locked 2207 kw Calculate under full-load voltage locked-rotor conditions a. Reactive power absorbed by the motor b. FR losses in the stator...
A 3-phase, 460 V, 1740 rpm, 60 Hz, 4-pole wound-rotor induction motor has the following parameters...
A 3-phase, 460 V, 1740 rpm, 60 Hz, 4-pole wound-rotor induction motor has the following parameters per phase: R1 = 0.25 Ω, ' 2R = 0.2Ω, ' 1 2 X = X = 0.5Ω, 30 m X = Ω. The rotational losses are 1700 W. With the rotor terminals short-circuited, find: 1. at starting: • current when started direct on full voltage, • a torque 2. at full load: • slip • current • ratio of starting current to full-load...
. A 460-V 460-V, 25-hp, 60-Hz, six-pole, Y-connected induction motor has the following impedanc ohms per phase referred to the stator circuit. Ri= 0.212 R2 = 0.282 X1 = 1.055 12 X2 = 1.055 22 XM = 33.9 W The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped with the rotational losses. For a rotor slip of 4% at the rated voltage and rated frequency, a) The input power b) Peony...
Problem # 3: Induction Motor Analysis [30 points] The parameters of the per phase equivalent circuit of a three phase wye-connected, 220 V (line- line, rms) 10 hp, 60 Hz, six-pole induction motor are given as: Ri = 0.3 Ohm, R2-0.15 Ohm, Xi-0.5 Ohms, X2= 0.2 Ohm, Xm-15.0 The total friction, windage and core losses add up to be a constant of 400 W. For a slip of 0.025 with motor operating at rated frequency and stator voltage, calculate the...
A 230 V, 50 Hz, three-phase, Y-connected, 6-pole induction motor has the following per-phase parameters R-0.07 Ro 00 0.08 Ω x, x, 0.3 xm 6.33 At a slip of 2%, determine the followings using approximate equivalent circuit of the motor i) The motor speed in rev/min and rad/s. ii) The rotor current. ii) The stator current. iv) The induced torque. v) The efficiency of the motor.
Please solve this question. Thank you.
A two-pole, 75kW, 440 V, 50 Hz, Y-connected, three-phase squirrel cage induction motor has the following parameters, in Ω/phase referred to the stator: R1-0.075, XI 0.17, xm-72, R2-0.065 and X-0.17. Its rated slip is 4%. Assume that the mechanical losses are 1 kW and the core losses are 1.1 kW. Compute: a. The rated input current b. The rated power factor. c. The pullout torque d. The induced and load torques at rated conditions....
1. A 15 hp, 4 pole, 208 V, 60 Hz, Y-connected, three-phase squirrel cage induction motor has the following parameters in Ω/phase referred to the stator: R,-0.220, Xi = 0.430, X,-15.0, R2 0.130 and X2-0.430. Mechanical and core losses amount to 300 W and 200 W respectively for rated voltage. (a) The motor is fed with a 60 Hz, 208 V voltage. It runs with a slip of 4.5 %. Find the speed, shaft torque and power, efficiency and power...
Name: 23. A 3-phase, 5000 hp, 6000 v,60 Hz, 12-pole wound-rotor induction motor has the 1, resistance between stator terminals-o12 Ω 2. resistance between rotor slip-rings-0.0073 Ω 3. windage and friction losses-51 kW following characteristics 4. iron losses in the stator-39 kW 5. locked rotor current at 6000 V-1800 A 6. active power to the stator with rotor locked 2207 kw Calculate under full-load voltage locked-rotor conditions a. Reactive power absorbed by the motor b. FR losses in the stator...
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