You need to estimate the mean number of travel days per year for outside salespeople. The mean of a small pilot study was 150 days, with a standard deviation of 36 days.
If you must estimate the population mean within 10 days, how many outside salespeople should you sample? Use the 95% confidence level.
Number of outside salespeople _______
Z Distribution Table:
Given that,
standard deviation = =36
Margin of error = E = 10
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z 0.025 = 1.96 ( Using z table ( see the 0.025 value in standard normal (z) table corresponding z value is 1.96 )
sample size = n = [Z/2* / E] 2
n = ( 1.96* 36 / 10 )2
n=49.787 ( rounded)
n =50
Sample size = n =50
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