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3-) Two parallel conducting plates have charges of +2x10-6C and -2x10-6C when connected to a potential difference of 10 v. 3-

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Answer #1

3-a)

  Capacitance \ C = \frac{q}{V}

C = \frac{2\times 10^{-6}}{10}

C = 0.2\mu F

3-b)

Energy stored

  U = \frac{1}{2}CV^2

  U = \frac{1}{2}\times 0.2\times10^{-6}\times10^2

U = 10\ \mu J

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