Question

Two rectangular parallel plates have area A and are separated by a distance d. They are connected to a power supply and charged with a voltage V. There no insulating material between them. In this configuration the plates make a capacitor with capacitance C. The electric field between the plates is E and the energy stored is U While still connected to the power supply, the plates are moved so the distance between them is one-half what it was. By what multiple do the following factors change? Capacitance 2 Voltage Difference 1/2 Electric Field- Charge on Plates-1/2 Energy Stored on Plates 2

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Answer #1

voltage = V. so 1 factor

electric field will become 2 time. as V =E*d

charge on capacitor will become 2 times.

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