Question

The plates of a parallel-plate capacitor each have an area of 0.1 m2 and are separated by a 1 mm thick layer of glass. The capacitor is connected to a 11 V battery. (The dielectric constant for glass is 5.)

a) Find the capacitance.

b) Find the charge stored.

c) Find the electric field between the plates.

Answer 1

A= 0.1m²

d= 1*10^-3m

V=11v

k=5

part a

c=K$\dpi{100} \epsilon_{0}$A/d=5*8.85 × 10^-12*0.1/1*10^-3=4.425*10^-9 F=4.425nF

part b

Q=CV=4.425*10^-9*11=4.8675*10^-8C

E =V/d=11/0.001=11*10³V/m