Question

The figure below shows a horizontal pipe with a varying cross section. A liquid with a density of 1.65 g/cm flows from left t
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Answer #1

(a)

use continuity equation

A1v1 = A2v2

10e-4 * 2.50 = 3.50e-4 * v2

v2 = 10e-4 * 2.50 / 3.50e-4

v2 = 7.14 m/s

_______

(b)

as the pipe is horizontal, we don't need to worry about height

so,

Bernoulli's equation gives

P1 + 1/2 * \rho * v1 ^ 2 = P2 + 1/2 * \rho * v2 ^ 2

1.20e5 + 1/2 * 1650 * 2.502 = P2 + 1/2 * 1650 * 7.142

solve for P2,

P2 = 8.31e4 Pa

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