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What is the entropy change in J/K to the universe when a dry ice (CO2) sculpture weighing 386.1 g sublimates on a table top a
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Answer #1

Answer- dSuniv 0.331 kJ/K

Mass of CO2 = 386.1 g

Molar mass of CO2 = 44 g/mol

Moles of CO2 = 389/MW = 386.1/44 = 8.775

heat required for sublimation of 1 mol of solid CO2= 21.6 kJ/mol

So, heat required for sublimation of 8.775 moles of solid CO2 = 8.775×21.6 = 189.54 kJ

dSuniv = dSsys + dSsurr

Using relation:

dS = q/T

dSsys = 189.54/(273-78.5) = 0.974 kJ/K

dSsurr = -189.54/(273+21.7) = -0.643 kJ/K

So,

dSuniv = 0.974 - 0.643 = 0.331 kJ/K

Your one thumbs up will help me lot. Thanks!

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