Answer- dSuniv 0.331 kJ/K
Mass of CO2 = 386.1 g
Molar mass of CO2 = 44 g/mol
Moles of CO2 = 389/MW = 386.1/44 = 8.775
heat required for sublimation of 1 mol of solid CO2= 21.6 kJ/mol
So, heat required for sublimation of 8.775 moles of solid CO2 = 8.775×21.6 = 189.54 kJ
dSuniv = dSsys + dSsurr
Using relation:
dS = q/T
dSsys = 189.54/(273-78.5) = 0.974 kJ/K
dSsurr = -189.54/(273+21.7) = -0.643 kJ/K
So,
dSuniv = 0.974 - 0.643 = 0.331 kJ/K
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