A sample of an ideal gas has a volume of 3.60 L at 13.80 °C and 1.80 atm. What is the volume of the gas at 19.00 °C and 0.991 atm?
we have:
P1 = 1.80 atm
P2 = 0.991 atm
V1 = 3.60 L
T1 = 13.8 oC
= (13.8+273) K
= 286.8 K
T2 = 19.0 oC
= (19.0+273) K
= 292 K
we have below equation to be used:
(P1*V1)/(T1) = (P2*V2)/(T2)
(1.8 atm*3.6 L)/(286.8 K) = (0.991 atm*V2)/(292.0 K)
V2 = 6.66 L
Answer: 6.66 L
Feel free to comment below if you have any doubts or if this answer do not work
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