Question

SUUU15 ? A sample of an ideal gas has a volume of 3.35 L at 13.80 °C and 1.30 atm. What is the volume of the gas at 20.40 C and 0.992 atm? V =

Answer 1

Ideal gas equation is PV = nRT

Where P is the pressure of the gas

V is the volume of the gas

n is the number of moles of the gas

R is the gas constant

T is the absolute temperature of the gas

For one mole of the gas, PV = RT

Let a gas occupies V_{​​​​​1} Volume at T_{​​​​​​1} temperature, P_{​​​​​​1} pressure

Pivi - = R - - - - - - - - - - > (1)

Let Volume of the gas changes to V_{​​​​​​2} volume when temperature and pressure are changed to P_{​​​​​​2} and

T_{​​​​​​2} respectively

P2V2 12 = R - - - - - - - - > (2)

From equations 1&2

PV EV, Ti Т)

$V_{2}=\frac{P_{1}V_{1}}{T_{1}} *\frac{T_{2}}{P_{2}}$

Given that

V_{​​​​​1}  = 3.35 L

P_{​​​​​​1} = 1.30 atm

T_{​​​​​​1} = 13.80°C = 13.8+273 = 286.80°C

V_{​​​​2}  = ?

P_{​​​​​2} = 0.992 atm

T_{​​​​​2} = 20.40°C = 20.4+273 = 293.4°C

V2 = 1.30atm * 3.35L 286,8 293.4K 0.992atm

final volume= 3.43 L