Question

Write a program that reads in a sentence of up to 100 characters and outputs the sentence with spacing corrected and with letters corrected for capitalization. In other words, in the output sentence, all strings of two or more blanks should be compressed to a single blank. The sentence should start with an uppercase letter but should contain no other uppercase letters. Do not worry about proper names; if their first letters are changed to lowercases, that is acceptable. Treat a line break as if it were a blank space, in the sense that a line break and any number of blank spaces are compressed to a single blank space. Assume that the sentence ends with a period and contains no other periods. For example, the input

Answer 1

Answer: Program #include #include <stdio.h> <string.h> int main ( ) char c[100] int ii.len; printf ("Enter a string : ") scanf ("%[^\n ] %*c", c); lenstrlen (c); while(c[il c[i+1]) for (i=i+1; slj ] = j<Len; j++) c[j+1]; en-- sli+1] c[i+1] -32; = else SLi+1]-c[i+1 32; printf ("%s\n", c) ; return 0;

Sample Output: Enter a string : abcd xyZiw Abcd Xyzw sh-4.3$ main Enter a string : abcd iJKlm Abcd Ijklm Nopq sh-4.3$ noPq

Copyable Code:

#include <stdio.h>
#include <string.h>

int main()
{
char c[100];
int i,j,len;
printf ("Enter a string : ");
scanf ("%[^\n]%*c", c);
len = strlen(c);
c[0] = c[0] - 32;
for (i=0; i<len; i++)
{
while(c[i] == c[i+1])
{
if (c[i] == ' ' && c[i+1] == ' ')
{
for(j=i+1; j<len; j++)
c[j] = c[j+1];
len--;
}
}

if (c[i] == ' ' && c[i+1] != ' ')
{
if (c[i+1] >= 'a' && c[i+1] <= 'z')
c[i+1] = c[i+1] - 32;
}
else
if (c[i+1] >= 'A' && c[i+1] <= 'Z')
c[i+1] = c[i+1] + 32;
  
}
printf("%s\n",c);
return 0;
}