Question

Previous Problem Problem List Next Problem (1 point) Find the absolute maximum and absolute minimum values of the function f(x)x3 122 27x+11 over each of the indicated intervals. (a) Interval [-2, 0] 1. Absolute maximum= 2. Absolute minimum (b) Interval [1, 101. 1. Absolute maximum=| 2. Absolute minimum (c) Interval [-2, 10] 1. Absolute maximum 2. Absolute minimum Note: You can earn partial credit on this problem. Preview My Answers Submit Answers You have attempted this problem 0 times. You have unlimited attempts remaining.

Answer 1

n= -1,97 are critical point cal f(x) = x12x²970 til f'in) = 3x²-241-27 f'(x)=0 as n²_8n-q=0 (-9) C4+1)0 f (n) = 6x-24 (a) interval [-2,80] at n=-2 ť" (1)= -12-24 = -36 Lo . f(x) ing has absolute manimum. at n=&o fico) = 680) - 24 solo f(x) has absolute minimum manimum & absolute manimum-value in c. 41-2) = -8- 48 +54 +1) != 9 8 710) = 11 -25 22 Hence absolute 700) = -1000 -1200-270+14 maximut -1459 at n=-). FC ) - 12 +27 + " absolute minimum ath to iso 97 I absolute minimum at n=-2 is a b [110] 2" (1) = 6-24_-18 co 2) = 6o-24 = 36 t o Hence of has absolute manimum at n=1 and abosute : minimum at na 10 *11) = 1-12-27 +1 = -27 #1-10) = -1459 10 [-2,107 fon) has absolute manimum at na-) A f(x) has absolute minimum at a los -1459 as