Question

5. Write a Complete C++ program which can produce the same result as shown below, i.e. convert numbers procedurally from decimal to binary, octal and hexadecimal. Microsoft Office 365 Excel supports number conversion from one base to another, for example from Decimal to Binary, Octal, Hexadecimal etc. One such example screen shot is attached here:

Answer 1

#include <iostream> using namespace std; // function to convert decimal to binary void decToBinary(int n) { // array to store binary number int binaryNum[32]; // counter for binary array int i = 0; while (n > 0) { // storing remainder in binary array binaryNum[i] = n % 2; n = n / 2; i++; } // printing binary array in reverse order for (int j - i - 1; j >= 0; j--) cout << binaryNum[j]; }

void decToHexa(int n) { // char array to store hexadecimal number char hexadeciNum[100]; // counter for hexadecimal number array int i = 0; while(n!=0) { // temporary variable to store remainder int temp = 0; // storing remainder in temp variable. temp = n % 16; // check if temp < 10 if(temp < 10) { hexadeci Num[i] = temp + 48; i++; } else temp + 55; hexadeciNum[i] i++; } n = n/16; } // printing hexadecimal number array in reverse order for(int j=i-1; j>=0; j--) cout << hexadeci Num[j]; }

6 // function to convert decimal to octal > void decToOctal(int n) // array to store octal number int octalNum[100]; 2 3 1 // counter for octal number array int i = 0; while (n != 0) { // storing remainder in octal array octalNum[i] = n % 8; n = n / 8; i++; } 2 3 // printing octal number array in reverse order for (int j - i - 1; j >= 0; j--) cout << octalNum[j]; 5

int main() { cout << "Decimal\t\tBinary\t\t\tOctal\tHexadecimal\n"; for (int loop = 0; loop <= 15; ++loop ) { cout << dec « loop << "\t\t"; // Output binary number decToBinary(loop); cout<<"\t\t\t"; decToOctal(loop); cout<<"\t"; decToHexa(loop); cout<<"\n"; } return; }

Input Decimal Binary Octal Hexadecimal 1 0 1 2 3 1 2 3 2 3 1 10 11 100 101 110 4 4 5 6 5 6 4 5 6 7 8 9 111 7 7 8 1000 1001 1010 10 11 12 9 10 A 11 1011 13 B 12 1100 14 C 13 15 D 14 1101 1110 1111 16 E 15 17 F Program finished with exit code 0 Press ENTER to exit console. I

source code:

#include <iostream>

using namespace std;

// function to convert decimal to binary
void decToBinary(int n)
{
// array to store binary number
int binaryNum[32];
  
// counter for binary array
int i = 0;
while (n > 0) {
  
// storing remainder in binary array
binaryNum[i] = n % 2;
n = n / 2;
i++;
}
  
// printing binary array in reverse order
for (int j = i - 1; j >= 0; j--)
cout << binaryNum[j];
}

// function to convert decimal to hexadecimal
void decToHexa(int n)
{
// char array to store hexadecimal number
char hexaDeciNum[100];
// counter for hexadecimal number array
int i = 0;
while(n!=0)
{ // temporary variable to store remainder
int temp = 0;
  
// storing remainder in temp variable.
temp = n % 16;
  
// check if temp < 10
if(temp < 10)
{
hexaDeciNum[i] = temp + 48;
i++; }
else
{
hexaDeciNum[i] = temp + 55;
i++; }
  
n = n/16; }
  
// printing hexadecimal number array in reverse order
for(int j=i-1; j>=0; j--)
cout << hexaDeciNum[j];
}
  
  
// function to convert decimal to octal
void decToOctal(int n)
{
  
// array to store octal number
int octalNum[100];
  
// counter for octal number array
int i = 0;
while (n != 0) {
  
// storing remainder in octal array
octalNum[i] = n % 8;
n = n / 8;
i++;
}
  
// printing octal number array in reverse order
for (int j = i - 1; j >= 0; j--)
cout << octalNum[j];
}   
  

int main()
{
cout << "Decimal\t\tBinary\t\t\tOctal\tHexadecimal\n";
for ( int loop = 0; loop <= 15; ++loop )
{
cout << dec << loop << "\t\t";
// Output binary number
decToBinary(loop);
cout<<"\t\t\t";
decToOctal(loop);
cout<<"\t";
decToHexa(loop);
cout<<"\n";

}
return 0;
}