Using
twotwo
of the letters of the alphabet, how many
fourfour-letter
codes can we form if we are allowed to use the same letter more than once?
We first need to select two letter out of 26 available which can be done in 26C2 i.e. 325 ways.
Now, for every letter in the code, we have 2 choices. Hence,
Total number of codes = 24 = 16
But in this, there would be 2 codes where all the four letter will be same but we need atleast two letters in code. Hence,
Number of possible codes for any 2 letter = 16 - 2 = 14
Therefore,
Total number of possible codes = 325*14 = 4550
Using twotwo of the letters of the alphabet, how many fourfour-letter codes can we form if...
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'-(oe : length(a)...
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