A spherical asteroid with radius of 18.6 km has uniform density 3500 kg/m3. Find the gravitational...

Question

Question

A spherical asteroid with radius of 18.6 km has uniform density 3500 kg/m3.

Find the gravitational acceleration at the asteroids surface

Express answer in two significant figures

Answer 1

Answer #1

Spherical astroid radius R = 18.6 km = 18600 m
density d = 3500 kg/m3

now mass of astroid is m = d*volume of the astroid

as astroid is spherical so volume of sphere v = 4/3 pi r^3

= 4/3 *3.14*(18.6*10^3)^3
= 2.694059712*10^13 m3

mass m = 2.694059712*10^13*3500
= 9.429208992*10^16 kg

now gravitational acceleration is g = G*M/R^2

g = 6.67408*10^-11 *9.429208992*10^16/(18.6*10^3)^2

g = 0.0181903385216 m/s2

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Answer 2

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