An object is 10 cm away from a lens with a -15 cm focal length (concave...
An object is 10 cm away from a lens with a -15 cm focal length (concave lens). Calculate the location of the image with the thin lens equation, and draw a ray tracing diagram of the lens. Use your preliminary calculations to set up the diagram well, choosing an appropriate scale and position for the lens.
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An object is 10 cm away from a lens with a -15 cm focal length
(concave...
A 0 cm tall object is placed 10 cm away from a concave mirror that has...
A 0 cm tall object is placed 10 cm away from a concave mirror that has a 4.0 cm focal length. Calculate the: Image distance Image Height Magnification A 1.0 cm tall object is placed 5 cm away from a biconcave lens that has a 10.0 cm focal length. Calculate the: Image distance Image Height Magnification Using the optics as configured in #5 & #6, Draw a ray-tracing diagram, with all principle rays. What is the nature of the image?
An object is placed 20 cm from a converging lens with focal length 15 cm. A concave mirror with...
An object is placed 20 cm from a converging lens with focal length 15 cm. A concave mirror with focal length 10 cm is located 75 cm to the right of the lens asshown in the figure. Note: The figure is not drawn to scale. A)Determine the location of the final image.B)If the height of the object is 1.0 cm, what is the height of the image?thanks!
An object is 6.0 cm in front of a converging lens with a focal length of 10 cm
An object is 6.0 cm in front of a converging lens with a focal length of 10cm.1. Use ray tracing to determine the location of the image.An object is 32 cm in front of a diverging lens with a focal length of 16 cm.2. Use ray tracing to determine the location of the image.
A 20 cm tall object is located 70 cm away from a diverging lens that has...
A 20 cm tall object is located 70 cm away from a diverging lens
that has a focal length of 20 cm. Use a scaled ray tracing to
answer parts a-d.
a. Is the image real or virtual?
b. Is the image upright or inverted?
c. How far from the lens is the image?
d. What is the height of the image?
e. Now use the thin lens equation to calculate the image
distance and the magnification equation to determine...
2. A thin converging lens has a focal length of 10.0 cm. An object is placed...
2. A thin converging lens has a focal length of 10.0 cm. An object is placed 30.0 cm from this lens. Use a sheet of the graph paper provided at the back of this manual to draw a ray diagram that shows the image formed by this lens. Use any two of the three principal (or special) rays and an appropriate scale. Hint: you could let 1 cm on your ray diagram represent 5 cm of the actual measurements:this scale...
A concave mirror has a focal length of 45 cm. An object is placed 35 cm...
A concave mirror has a focal length of 45 cm. An object is placed 35 cm from the mirror. a. Draw the ray tracing diagram to locate the image. Is the image real or virtual? b. Calculate the image location and the magnification for the image. Compare your results with part a. c. What would the image location and magnification be if the object were 55 cm from the mirror?
An object is located 40.0 cm from the front side of a divergent lens. A focal point of the lens is located at 20.0 cm from the front side of the lens. (a) Determine the location of the image form...
An object is located 40.0 cm from the front side of a divergent lens. A focal point of the lens is located at 20.0 cm from the front side of the lens. (a) Determine the location of the image formed. (b) Determine the size of the image if the object is 12.0 cm tall. (c) Draw a ray tracing diagram showing the location of the object, image and lens.
An object is located 40.0 cm from the front side of...
An object is 15 cm in front of a diverging lens with a focal length of...
An object is 15 cm in front of a diverging lens with a focal length of 10 cm. Part A Use ray tracing to determine the location of the image. Express your answer using two significant figures. q = Part B Is the image upright or inverted? Part C Is the image real or virtual?
1. An object is 29 cm in front of a convex lens with a focal length...
1. An object is 29 cm in front of a convex lens with a focal length of 10 cm. Using ray tracing and thin lens equation, determine whether the image is real or virtual, upright or inverted, reduced or magnified.
A 4.0-cm tall object is placed 50.0 cm from a diverging lens having a focal length...
A 4.0-cm tall object is placed 50.0 cm from a diverging lens having a focal length of magnitude 25.0 cm. Draw the ray diagram for this situation. What is the location and height of the image? Is the image real or virtual? • Draw an optical axis with the lens centered on the axis. Represent the object at the correct distance from the lens • Draw the three "special rays" from the top of the object • Extend the rays...
A 20 cm tall object is located 70 cm away from a diverging lens
that has a focal length of 20 cm. Use a scaled ray tracing to
answer parts a-d.
a. Is the image real or virtual?
b. Is the image upright or inverted?
c. How far from the lens is the image?
d. What is the height of the image?
e. Now use the thin lens equation to calculate the image
distance and the magnification equation to determine...
2. A thin converging lens has a focal length of 10.0 cm. An object is placed 30.0 cm from this lens. Use a sheet of the graph paper provided at the back of this manual to draw a ray diagram that shows the image formed by this lens. Use any two of the three principal (or special) rays and an appropriate scale. Hint: you could let 1 cm on your ray diagram represent 5 cm of the actual measurements:this scale...
An object is located 40.0 cm from the front side of a divergent lens. A focal point of the lens is located at 20.0 cm from the front side of the lens. (a) Determine the location of the image formed. (b) Determine the size of the image if the object is 12.0 cm tall. (c) Draw a ray tracing diagram showing the location of the object, image and lens.
An object is located 40.0 cm from the front side of...
1. An object is 29 cm in front of a convex lens with a focal length of 10 cm. Using ray tracing and thin lens equation, determine whether the image is real or virtual, upright or inverted, reduced or magnified.
A 4.0-cm tall object is placed 50.0 cm from a diverging lens having a focal length of magnitude 25.0 cm. Draw the ray diagram for this situation. What is the location and height of the image? Is the image real or virtual? • Draw an optical axis with the lens centered on the axis. Represent the object at the correct distance from the lens • Draw the three "special rays" from the top of the object • Extend the rays...
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