Question

A 170 cm sample of soil obtained from below the ground water table has a mass of 300 g. When oven-dried, the mass is 210 g. What is the density of solid soil particles? (Formulae attached) Phase relationships in soils S, = WG p=Pa(1+w) p=GWm y'= 7 sat – Yw 1. =D, = {max e x100 emax - emin a. 2.60 g/cm3 b.2.63 g/cm3 OC.2.67 g/cm3 d. 2.70 g/cm3

Answer 1

HUS 2 Given, V = 170cm Meat = 300g Mabry-210g To calculate (lading ) Scotron - Msotucated – Boog Dog - = 1.76 g/cm² 70 Total 170 cm (1.7647) Maat - Mary Water content, wo Mwakr = M solid Morey = 300 - 210 = 9 = 0,42857 solid = Msolid , We have to calculate the V solid value of solid - Voolid can be calculated by Veolid = V Total - e - void radio ite We know se=wG & Vsat = (te) Xw sot = 1.76 = (Git word vw tox saturated s = 1 it WG G(1+0,428) x 1 7 1.76477 Gll+w) Vw - 1+ WG + 0.428 G Ite 1.4286 =1.76 + 0.75 3267 = > G1 = 2.625

Appling se=wG e = 0.428 X 2.625 < =wG => e = 1.125 Vsolid = VI The = 170 + 1.125 = 80cm3 +1,120 Soin = Meonid = 210g Veolid 80 cm3 ~ 2.63 g/cm² of solid pactices is Hence the density 2.63 g/cm3

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