Question

2.1- Analyze the circuit shown in figure (2); find the diode states by using ideal- (4 Marks) diode model. Starting by assuming D1 is off and D2 is on. D2 Figure (2)

Answer 1

We found this as -

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We have, It D_1 is off & D_2 is ON, we have: By redrawing circuit, I implies 3/6 k implies 0..5 mA Now, let�s check which diode is ON or off by considering initially both diodes are ON \r\n If both diodes are ON, then they will behave as a short circuit therefore By KCL, we have I_1 + I_2 implies I & voltage also ss 6 k will be 3 v therefore 10 - 3/4 k implies I, I implies 3/6 k \r\n therefore I_2 implies = -7/4 k + 3/6 k I_2 implies - 1.75 mA + 0.5 mA I_2 implies - 1.25 mA Here, you can see I_2 is negative, therefore D_2 will as in reserve bias mode means off therefore Diode stats D_1 implies ON D_2 implies off New event values: - therefore I implies 10/10 k implies 1 mA