Homework Answers
(A) Applying work - energy theorem,
Work done by spring + work done by friction = change in KE
-(400)(d^2)/2 + (- 10 d) = 0 - 20
200 d^2 + 10d - 20 = 0
d = 0.292 m
(B) Work done by friction = - 2 (10 x 0.292)
= 5.84 J
Kf = 20 - 5.84 = 14.2 J
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