Question

(Ch 30 Alternative Exercise 30.86 The equation -iR-L --0 may be converted into an energy relationship. Muitiply both sides of this equation by -i-da/dt. The first term then becomes i R Part A Show that the second term can be written as d (; Li) /dt, and that the third term can be writen as d (/2C) /dt. Essay answers are limited to about 500 words (3800 characters maximum, Including spaces). 3800 Character(s remaining Request Answer Submit Part B What does the resulting equation say about energy conservation in the circuit? Essay answers are limited to about 500 words (3800 characters maximum, Including spaces). 3800 Character(s) remaining Submit Request Answer Provide Feedback MacBook Air

Answer 1

Lecond term = ildi Energy etored in inductor fli? Rate of change in energy = fut la Ley 12 ei ole equation - R -Ladie - no multiply both sides by -{{R- Lidi - iq =0 Kate of Energy loss in resistor, inductor and conductos sum up to o so total energy is conserved Energy stored in capacitor - 2 du er (23) as da = i due = a i

**R + li de tine 30 * d ( UR + Ų + Uc) = Energy stored in resistor, inductor and capacitor is constant : as rate of change in energy in resistor, inductor 'and capacitor is o.

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