Horizontal component, Ax = A cos
= 5 x cos(30)
= 5 x 0.866
= 4.33
Vertical component, Ay = A sin
= 5 x sin(30)
= 5 x 0.5
= 2.5
(Ax, Ay) = (4.33, 2.5)
Problems: 1) Given Mag and Direction - Get Components (5,30 ) An Ast
Number 8 In each of Problems 7 through 10, draw a direction field for the given differential equation. Based on the direction field, determine the behavior of y ast oo. If this behavior depends on the initial value of y at t 0, describe this dependency. Note that in these problems the equations are not of the form y ay+b, and the behavior of their solutions is somewhat more complicated than for the equations in the text.
In each of Problems 1 through 4 draw a direction field for the given differential equations. Based on the direction field, determine the behavior of y as t → +∞. If this behavior depends on the initial value of y at t = 0, describe this dependency. 1. y ' = 3 + 2y 2. y ' = 3 − 2y 3. y ' = −y(5 − y) 4. y ' = y(y − 2)2
Given the x and y components of the velocity vector, find the magnitude and direction of the resultant vector. V & P i ug = 18% V 21"} Vas-Ho" - 22/s
Given an electric dipole as shown in figure 1 1. Given an electric dipole as shown in Figure a) khat is the force (mag. & dir.) exerted by the charge b) いn a t is the electric field (cag, & dir.) at point A? c) What is the electric potential at point A? d) hat is the electric potential at point B.o much work woule en the + charge? you do in moving an electron(q =-1.6 x 10./9 C) fron...
b) Calculate the components of the vector C c) Find the magnitude and direction of the vector C 1.) The vector A is given by the magnitude |A4.4 cm and the direction with respect to the +1-axis θΑ-140°. The vector B is given by the r-component Bz-4.4 cm and the y-component By3.2 cm
Date ast Name First name M.I te: Show all the details of your calculation to get full credit. 1. An object, 4.0 cm high, is placed 20 cm in front of a concave spherical mirror of 40 cm focal length. a) Find the location of its image b) Find its magnification and final size of the image.
Activity 1-6: Addition and Subtraction of Vectors by Components If we add two vectors, we can break up the addition by components. For example Since the x-components point in the same (or opposite direction), we can add the values of the components separately to get the overall vector component in that direction. Once we have the overall components, we can get the magnitude of the vector and its direction by using Pythagorean's theorem and trigonometry. In what follows, we will...
(1 point) Given the components of the vectors A and B A -9.59, A,-6.09 B,-5.12, B,-2.23 find the following quantities: The length and direction of each vector: AI = B= The components of C The length and direction of C: 101 = C=
1. Given a vector V with x- and y- components Vx = -6.2 and Vy = 2.9. What is the magnitude of vector V? 2. Given a vector V with x- and y- components Vx = -4.5 and Vy = 3. What is the direction of vector V with respect to the +x-axis counterclockwise?
In this problem, the x and y components of four vectore are given. You will find the magnitude and the direction of the vectors. Report the direction with an angle (in degrees) COUNTERCLOCKWISE from +x axis. Keep 2 decimal places in all answers. -The x and y components of vector A are given as: Ax = 6.0 m, Ay = 8.0 m Its magnitude is: -The direction of vector A (in degrees) is : -The x and y components of...