ANSWER:
Young's modulus for mixture is defined as:
E = Ef Vf + Em Vm
Here: f = fiber ; m = epoxy matrix ; v = volume fraction;
From the given data:
Ef = 70Gpa , f = 1Gpa , Vf = 0.6
Em = 3Gpa , m = 60mpa , Vm = 0.4
Then,
Young's modulus E = (70) (0.6) + (3)(0.4)
E = 43.2Gpa
For Lognitudinal strain:-
fiber ---> Ef = f / Ef = 1/70 = 0.0142
epoxy matrix ---> Em = m / Em = 60(106) / 3(109) = 0.2
So, from fiber and epoxy matrix we can write as
Ef < Em
So, m' = Em * Ef = (3) (0.0142) = 0.0426Gpa
From tensile strength:-
= f Vf + m' Vm
= (0.6)+(1) + (0.4) (0.0426)
= 0.6 + 0.01704
= 0.61704Gpa
= 617.04Mpa
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