Calculate the lattice energy for LiF(s) given the following: sublimation energy for Li(s) = +166 KJ/mol...

Question

Question

Calculate the lattice energy for LiF(s) given the following:

sublimation energy for Li(s) = +166 KJ/mol

delta Hf for F(g) = +77 KJ/mol

first ionization energy of Li(g) = +520 KJ/mol

electron affinity of F(g) = -328 KJ/mol

enthalpy of formation of LiF(s) = -617 KJ/mol

Answer 1

Answer #1

Elect on ) LIF ahioa LaHice n > Li a) hatfice enen he aMou

Answer 2

Similar Homework Help Questions

Consider the following information. The lattice energy of LiCl is ΔH lattice = −834 kJ/mol. The...

Consider the following information. The lattice energy of LiCl is ΔH lattice = −834 kJ/mol. The enthalpy of sublimation of Li is ΔH sub = 159.3 kJ/mol. The first ionization energy of Li is IE 1 = 520 kJ/mol. The electron affinity of Cl is ΔH EA = -349 kJ/mol. The bond energy of Cl2 is BE = 243 kJ/mol. Determine the enthalpy of formation, ΔHf, for LiCl(s).
Given the following information, calculate the lattice energy of CaF2 The enthalpy of formation of CaF2...

Given the following information, calculate the lattice energy of CaF2 The enthalpy of formation of CaF2 -1228 kJ/mol Heat of sublimation of Ca 177.8 kJ/mol Bond dissociation energy of F2 159 kJ/mol First ionization energy of Ca 589.8 kJ/mol Second ionization energy of Ca 1145.4 kJ/mol . Electron affinity of F -328 kJ/mot [ Answer : -2644 KJİ I
Using the thermodynamic quantities shown below: construct a Born-Haber cycle for the following reaction: Li(s) +...

Using the thermodynamic quantities shown below: construct a Born-Haber cycle for the following reaction: Li(s) + 1/2 F2(g) LiF(s); calculate the lattice energy of LiF. Vaporization of Li(s): +159 F2 bond enthalpy: +155 Li ionization energy: +520 F- electron affinity: +328 LiF(s) heat of formation: -616

Consider the following information. The lattice energy of NaCl is ΔH lattice=−788 kJ/mol The enthalpy of...

Consider the following information. The lattice energy of NaCl is ΔH lattice=−788 kJ/mol The enthalpy of sublimation of Na is ΔHsub=107.5 kJ/mol The first ionization energy of Na is IE1=496 kJ/mol. The electron affinity of Cl is ΔHEA=−349 kJ/mol. The bond energy of Cl2 is BE=243 kJ/mol. Determine the enthalpy of formation, ΔHf, for NaCl(s). ΔHf= kJ/mol
Consider the following information. • The lattice energy of NaCl is AHlattice = –788 kJ/mol. •...

Consider the following information. • The lattice energy of NaCl is AHlattice = –788 kJ/mol. • The enthalpy of sublimation of Na is AHsub = 107.5 kJ/mol. • The first ionization energy of Na is IE1 = 496 kJ/mol. • The electron affinity of Cl is AHEA = -349 kJ/mol. • The bond energy of Cl, is BE = 243 kJ/mol. Determine the enthalpy of formation, AHf, for NaCl(s). AH= kJ/mol
Consider the following information. • The lattice energy of KCl is AHlattice = -701 kJ/mol. •...

Consider the following information. • The lattice energy of KCl is AHlattice = -701 kJ/mol. • The enthalpy of sublimation of K is AHsub = 89.0 kJ/mol. • The first ionization energy of K is IE1 = 419 kJ/mol. • The electron affinity of Cl is AHEA = -349 kJ/mol. • The bond energy of Cl, is BE = 243 kJ/mol. Determine the enthalpy of formation, AHf, for KCl(s). AHư= kJ/mol

3. Draw the Bom Haber Cycle and calculate the lattice energies for LiF, MgO, and CaC12...

3. Draw the Bom Haber Cycle and calculate the lattice energies for LiF, MgO, and CaC12 using the data provided in the table below. This can be done on a separate page if you are working off this template. AH (1/2 B.E.) Electon Affinity Ionization Sublimation AH EA Energy Ionic Compoud F 80 kJ/mol 328 kJ/mol Li 520 kJ/mol 155 kJ/mol LiF -594 kJ/mol 0 249.4 kJ/mol 141 kJ/mol (15) . Mg 738 kJ/mol (19) 148 kJ/mol MgO -601 kJ/mol...
2. Use the following data to calculate the lattice energy (U) of NaCl(s) from sodium me...

2. Use the following data to calculate the lattice energy (U) of NaCl(s) from sodium me chlorine: Enthalpy of formation (4H) for NaCl(s) - -411 kJ/mol Enthalpy of sublimation (4Hub) of Na 107.3 kJ/mol The first ionization energy of Na (E,)-495.8 kJ/mol The bond dissociation energy (D) of Clh- 243 kJ/mol The electron affinity of Cl (Eea)- 348.6 kJ/mol.
b) Given the following data, calculate the lattice energy for silver iodide. Enthalpy of sublimation of...

b) Given the following data, calculate the lattice energy for silver iodide. Enthalpy of sublimation of silver = +286 kJmol Enthalpy of sublimation of iodine : +107 kJmol.' Enthalpy of dissociation of iodine : +151 kJmol Ionisation energy of silver : +730 kJmol? Electron affinity of iodine : -295 kJmol Enthalpy of formation of AgI : -62 kJ moll